我记得那样的对象
{
"data": "some data",
"social": {
"twitter": "id"
}
}
使用下一个类
可以轻松解析public class SocialLinks {
@Expose
private String data;
@Expose
private Social social;
}
public class Social {
@Expose
private String twitter;
}
不幸的是,由于某些问题,如果社交是空的,那么它将被视为数组
{
"data": "some data",
"social": [
]
}
如何用gson解析它? (我不是服务器端的开发人员,不能影响响应时间)
答案 0 :(得分:1)
你可以使用这些类来做到这一点。
SocialLinks.java
public class SocialLinks {
private String data;
private Social social;
// Getters && Setters
}
Social.java:
public class Social {
private String twitter;
// Getters & Setters
}
这是你的主要方法
public class GsonApp {
private static final String TEST_JSON = "{\n" +
" \"data\": \"some data\",\n" +
" \"social\": {\n" +
" \"twitter\": \"id\"\n" +
" }\n" +
"}";
public static void main(String[] args) throws Exception {
final Gson gson = new GsonBuilder().create();
// Read Example
final SocialLinks socialLinks = gson.fromJson(TEST_JSON, SocialLinks.class);
System.out.println(gson.toJson(socialLinks));
// Write with null Social
final SocialLinks socialLinks1 = new SocialLinks();
socialLinks1.setData("MyData");
System.out.println(gson.toJson(socialLinks1));
// Write with empty Social (social.twitter is null)
final SocialLinks socialLinks2 = new SocialLinks();
socialLinks2.setData("MyData");
socialLinks2.setSocial(new Social());
System.out.println(gson.toJson(socialLinks2));
// Write with full Social
final SocialLinks socialLinks3 = new SocialLinks();
socialLinks3.setData("MyData");
socialLinks3.setSocial(new Social());
socialLinks3.getSocial().setTwitter("ID");
System.out.println(gson.toJson(socialLinks3));
}
}
这将输出
{"data":"some data","social":{"twitter":"id"}}
{"data":"MyData"}
{"data":"MyData","social":{}}
{"data":"MyData","social":{"twitter":"ID"}}
如果根据应用程序状态更改数据类型,则可能需要创建Map对象而不是DTO。这是一个例子
private static final String TEST_JSON_2 = "{\n" +
" \"data\": \"some data\",\n" +
" \"social\": [\n" +
" ]\n" +
"}";
...
Type type = new TypeToken<Map<String, Object>>(){}.getType();
final Map<String, Object> socialLinks4 = gson.fromJson(TEST_JSON_2, type);
System.out.println(socialLinks4);
final Map<String, Object> socialLinks5 = gson.fromJson(TEST_JSON, type);
System.out.println(socialLinks5);
这将输出
{data=some data, social=[]}
{data=some data, social={twitter=id}}