Question

我正在寻找一种方法将html表格插入电子邮件正文（未附加/未链接）。

到目前为止我做了什么，而且还不够好：

1：将表格作为文件附加到邮件中。

2：将html转换为csv并粘贴到电子邮件正文。

3：添加了一个指向邮件的超链接，其中包含指向表格的链接。

尝试使用Mailer和email.MIMEMultipart

我想我错过了什么，看起来很琐碎。感谢

Answer 1

来自Python email documentation - 18.1.11. email: Examples：

以下是如何使用替代方法创建HTML消息的示例纯文本版本：

#! /usr/bin/python

import smtplib

from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

# me == my email address
# you == recipient's email address
me = "my@email.com"
you = "your@email.com"

# Create message container - the correct MIME type is multipart/alternative.
msg = MIMEMultipart('alternative')
msg['Subject'] = "Link"
msg['From'] = me
msg['To'] = you

# Create the body of the message (a plain-text and an HTML version).
text = "Hi!\nHow are you?\nHere is the link you wanted:\nhttp://www.python.org"
html = """\
<html>
  <head></head>
  <body>
    <p>Hi!<br>
       How are you?<br>
       Here is the <a href="http://www.python.org">link</a> you wanted.
    </p>
  </body>
</html>
"""

# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')

# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
msg.attach(part1)
msg.attach(part2)

# Send the message via local SMTP server.
s = smtplib.SMTP('localhost')
# sendmail function takes 3 arguments: sender's address, recipient's address
# and message to send - here it is sent as one string.
s.sendmail(me, you, msg.as_string())
s.quit()

Python，将HTML表格插入电子邮件正文（未附加）

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