Question

我需要在laravel 5中处理$scope.formData = {}; //...also $scope.formData = []; works too，这样如果令牌不匹配，它会向用户显示一些消息而不是TokenMismatchException错误。

Answer 1

您可以在App\Exceptions\Handler课程中创建自定义exception render（在/app/Exceptions/Handler.php文件中）。

例如，要在TokenMismatchException错误时呈现不同的视图，您可以将render方法更改为以下内容：

/**
 * Render an exception into an HTTP response.
 *
 * @param  \Illuminate\Http\Request  $request
 * @param  \Exception  $e
 * @return \Illuminate\Http\Response
 */
public function render($request, Exception $e)
{
    if ($e instanceof \Illuminate\Session\TokenMismatchException) {
        return response()->view('errors.custom', [], 500);
    }
    return parent::render($request, $e);
}

Answer 2

您需要编写一个函数来呈现TokenMismatchException错误。您将以这种方式将该函数添加到App \ Exceptions \ Handler类（在/app/Exceptions/Handler.php文件中）：

// make sure you reference the full path of the class:
use Illuminate\Session\TokenMismatchException;

class Handler extends ExceptionHandler {

    protected $dontReport = [
        HttpException::class,
        ModelNotFoundException::class,
        // opt from logging this error to your log files (optional)
        TokenMismatchException::class,
    ];

    public function render($request, Exception $e)
    {
        // Handle the exception...
        // redirect back with form input except the _token (forcing a new token to be generated)
        if ($e instanceof TokenMismatchException){
            return redirect()->back()->withInput($request->except('_token'))
            ->withFlashDanger('You page session expired. Please try again');
        }

在laravel 5中处理TokenMismatchException

2 个答案: