我有一个像这样的XML文件:
<hierachy>
<att>
<Order>1</Order>
<attval>Data</attval>
<children>
<att>
<Order>1</Order>
<attval>Studyval</attval>
</att>
<att>
<Order>2</Order>
<attval>Site</attval>
</att>
</children>
</att>
<att>
<Order>2</Order>
<attval>Info</attval>
<children>
<att>
<Order>1</Order>
<attval>age</attval>
</att>
<att>
<Order>2</Order>
<attval>gender</attval>
</att>
</children>
</att>
</hierachy>
我正在尝试将其转换为CSV文件,如下所示:
Data,Studyval
Date,Site
Info,age
Info,gender
我的问题是,父名和子名都是相同的 - 'att'和'attval'。我如何告诉Python区分两者并给我输出?
我试过了:
import xml.etree.cElementTree as ET
tree = ET.parse('input.xml')
rebase = tree.getroot()
list = []
for att in rebase.findall('att'):
name = att.find('attval').text
for each_att in att.findall('attval'):
try:
val = att.find('attval').text
print name, val
except AttributeError:
print name
它打印了两次相同的东西。
答案 0 :(得分:7)
不要使用findall
函数,因为它会在整个树中查找att标记。只需按顺序从上到下迭代树,然后抓住它们中的相关元素。
from xml.etree import ElementTree
tree = ElementTree.parse('input.xml')
root = tree.getroot()
for att in root:
first = att.find('attval').text
for subatt in att.find('children'):
second = subatt.find('attval').text
print('{},{}'.format(first, second))
给出了:
$ python process.py
Data,Studyval
Data,Site
Info,age
Info,gender