比较2个字符串是否是彼此的字谜

Question

我只是想问一下我的代码有什么问题，因为它没有输出2个单词是anagram。感谢任何帮助。

公共课程计划{

public static void main(String[] args){
    String word1 ="test";
    String word2 = "tset";
    boolean output = isAnagram(word1,word2);
    System.out.println("isAnagram:"+output);
}

public static boolean isAnagram(String word1, String word2){ 
       boolean output = false;
       boolean found = false;
       int x = 0;
       int ctr = 0;
          for(int i=0; i<word1.length()-1;i++){

          x=0;
          found=false;

          while(found!=true){
              if(word1.charAt(x)==word2.charAt(i)){
                  ctr++;
                  found=true;
              }

              else{

                  x++;
              }
          }}
       if(ctr==word1.length()&&ctr==word2.length()){
           output = true;
       }
        return output;
    }}   

Answer 1

public static boolean isAnagram(String word1, String word2){ 

   boolean isAnagram = false;
   int x = 0;
   int ctr = 0;
    if(word1.length() == word2.length()){
    int n = 0;
    for(int c = word2.length(); c > 0 && n < word2.length() , c++ ){
if(word1.charAt(n).equals(word2.charAt(c))){
x++;
}
n++;
}
if(x == word1.length())
isAnagram == true;
}  
    return isAnagram;
}}   

  

    

这将取第一个和最后一个字母或字符，并在第二个字母上计数，并在第二个字母上计数。