如果问题不对,我道歉,因为我不确定这个问题的正确措辞/语法......
Get-View -ViewType VirtualMachine | Where { $_.Guest.GuestFullname} | Sort Name |Select-Object Name, @{N=”SelectedOS”;E={$_.Guest.GuestFullName}}, @{N=”InstalledOS”;E={$_.Summary.Config.GuestFullName}} | Out-GridView
如何比较和匹配要输出的“SelectedOS”和“InstalledOS”的数据。
例如,当前脚本将输出:
Name SelectedOS InstalledOS
---- ---------- -----------
VM-Demo-CCMIVR-1 Microsoft Windows Server 2012 (64-bit) Microsoft Windows Server 2012 (64-bit)
VM-Demo-vMCD2 Other 2.6.x Linux (32-bit) CentOS 4/5/6 (32-bit)
VM-Inf-CUC-10-5 Red Hat Enterprise Linux 6 (64-bit) Red Hat Enterprise Linux 6 (64-bit)
VM-Inf-CUCM-10-5 Red Hat Enterprise Linux 6 (64-bit) Red Hat Enterprise Linux 6 (64-bit)
VM-Inf-DC01 Microsoft Windows Server 2012 (64-bit) Microsoft Windows Server 2012 (64-bit)
但我只想看:
Name SelectedOS InstalledOS
---- ---------- -----------
VM-Demo-CCMIVR-1 Microsoft Windows Server 2012 (64-bit) Microsoft Windows Server 2012 (64-bit)
VM-Inf-CUC-10-5 Red Hat Enterprise Linux 6 (64-bit) Red Hat Enterprise Linux 6 (64-bit)
VM-Inf-CUCM-10-5 Red Hat Enterprise Linux 6 (64-bit) Red Hat Enterprise Linux 6 (64-bit)
VM-Inf-DC01 Microsoft Windows Server 2012 (64-bit) Microsoft Windows Server 2012 (64-bit)
答案 0 :(得分:3)
如果我看对了你,你想要比较并且只显示那些" SelectedOS"和" InstalledOS"是相同的。为此,您需要-eq
语句中的Where
。像这样:
Where { $_.Guest.GuestFullname -eq $_.Summary.Config.GuestFullName }
所以你的代码变成了。
Get-View -ViewType VirtualMachine | Where { $_.Guest.GuestFullname -eq $_.Summary.Config.GuestFullName } | Sort Name |Select-Object Name, @{N=”SelectedOS”;E={$_.Guest.GuestFullName}}, @{N=”InstalledOS”;E={$_.Summary.Config.GuestFullName}} | Out-GridView