Question

我正在尝试根据用户的电子邮件地址创建3个文件夹。我有一个主文件夹，然后是以电子邮件地址命名的文件夹，最后是一个名为images或tracks或chains的文件夹。我将路径传递给应该创建它们的函数。然而，一切都没有发生。你能告诉我我做错了什么吗？

public function createFolder($email){
    $this->email=$email;
    $this->pictureDirectoryPath = "../Uploads/$this->email/images";
    $this->uploadedTracksPath = "../Uploads/$this->email/tracks";
    $this->chainsPath = "../Uploads/$this->email/chains";

    //Calling the function doIt(path) to create the acutal directory.
    //The desired path is passed as a parameter

     doIt($this->pictureDirectoryPath);
     doIt($this->uploadedTracksPath);
     doIt($this->chainsPath);

}

//Function doIt() which is supposed to create a directory 
//However, nothing happens when it is called..
public function doIt($path){
    if (!mkdir($path, 0777, true)) {
            die('Failed to create folders...');
        }
}

Answer 1

要调用类中的函数/方法，您需要添加$this->或self::，具体取决于它是否为静态。

 $this->doIt($this->pictureDirectoryPath);
 $this->doIt($this->uploadedTracksPath);
 $this->doIt($this->chainsPath);

PHP mkdir函数在调用时返回错误

1 个答案: