Question

我正在整合第三方REST API。我已经为给定的json编写了pojo。表格第三方我以json的形式得到回应

"custom_fields": {
            "Field_68092": {
                "type": "char", 
                "required": true, 
                "value": "1", 
                "label": "orderId"
            }
        }

我尝试了以下POJO

public class Field_68092 {
    private String type;
    private String value;
    private String label;
    private boolean required;

    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    public String getValue() {
        return value;
    }

    public void setValue(String value) {
        this.value = value;
    }

    public String getLabel() {
        return label;
    }

    public void setLabel(String label) {
        this.label = label;
    }

    public boolean isRequired() {
        return required;
    }

    public void setRequired(boolean required) {
        this.required = required;
    }
}

和自定义文件的pojo是

public class Custom_fields {
    private Field_68092 Field_68092;

    public Field_68092 getField_68092() {
        return Field_68092;
    }

    public void setField_68092(Field_68092 field_68092) {
        Field_68092 = field_68092;
    }
}

Field_68092每次都为null。有人能帮我找到POJO结构有什么问题吗？

Answer 1

我觉得你的POJO没问题。请尝试使用此JSON

{"field_68092":{"value":"1","type":"char","label":"orderId","required":true}}

Answer 2

如果你使用杰克逊，你应该使用额外的注释

@JsonTypeInfo(include = JsonTypeInfo.As.WRAPPER_OBJECT, use = JsonTypeInfo.Id.NAME)
public class Field_68092 {

而custom_fields它不是类名 - 它是其他类中的字段名

我检查，一切顺利

付款类：

import com.fasterxml.jackson.annotation.JsonTypeInfo;

@JsonTypeInfo(include = JsonTypeInfo.As.WRAPPER_OBJECT, use = JsonTypeInfo.Id.NAME)
 public class Payment {
     private Field_68092 custom_fields;

     public Field_68092 getCustom_fields() {
         return custom_fields;
    }

    public void setCustom_fields(Field_68092 custom_fields) {
        this.custom_fields = custom_fields;
    }
}

Field_68092类

import com.fasterxml.jackson.annotation.JsonTypeInfo;

@JsonTypeInfo(include = JsonTypeInfo.As.WRAPPER_OBJECT, use = JsonTypeInfo.Id.NAME)
    public class Field_68092 {
    private String type;
    private String value;
    private String label;
    private boolean required;

    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    public String getValue() {
        return value;
    }

    public void setValue(String value) {
        this.value = value;
    }

    public String getLabel() {
        return label;
    }

    public void setLabel(String label) {
        this.label = label;
    }

    public boolean isRequired() {
        return required;
    }

    public void setRequired(boolean required) {
        this.required = required;
    }
}

简单测试：

import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.StringWriter;

public class Main {

    public static void main(String[] args) throws Exception{
        Payment p = new Payment();
        Field_68092 f = new Field_68092();
        f.setLabel("label");
        f.setRequired(false);
        f.setType("type");
        f.setValue("value");
        p.setCustom_fields(f);

        ObjectMapper m = new ObjectMapper();
        StringWriter w = new StringWriter();
        m.writer().writeValue(w, p);
        System.out.println(w.getBuffer());
        String json = "{\"Payment\":{\"custom_fields\":{\"Field_68092\":{\"type\":\"type\",\"value\":\"value\",\"label\":\"label\",\"required\":false}}}}";
        Payment p2 = m.readValue(json, Payment.class);
        System.out.println(p2.getCustom_fields());
    }
}

对于给定的JSON

2 个答案: