Question

您好我正在制作出席日期。在一个领域中有多个值用于出勤状态，如1表示缺席，3表示缺席，

例如：

public function attendanc_disc($site_id)
{
    $y=date('Y-m');
    $sql = "SELECT sch.*"
            ." FROM #__schedule AS sch"
            ." WHERE sch.start_date like '%".$y."%' and sch.site_id='".$site_id."' order by sch.start_date ASC"
            ;
        $query = $this->db->query($sql);
    return $query->result();
}

对于BAY这个日期2015-08-02应该显示一行，当前值应该是2，但我得到两行。

这是我的代码：

foreach ($sch_rows as $sch) {



                if ($sch->reply_status_id == 1) {
                    $presentcnt +=1;
                    $class = 'success';
                } else if ($sch->reply_status_id == 0) {
                    $not_res +=1;
                    $class = 'warning';
                } else if ($sch->reply_status_id == 6) {
                    $CB_res +=1;
                    $class = 'alert-info';
                } else {
                    $absent +=1;
                    $class = 'alert-danger';
                }


                $html .='<tr ><td class="' . $class . '"><a href="admin/schedule/assignment/true/' . $site->id . '" >' . $site->code . '</a></td><td><a href="index.php/admin/home/att_report/1/' . $site->id . '">' . $sch->start_date . '</a></td><td><a href="index.php/admin/home/att_report/1/' . $site->id . '">' . $presentcnt . '</a></td><td><a href="index.php/admin/home/att_report/1/' . $site->id . '">' . $absent . '</a></td><td><a href="index.php/admin/home/att_report/2/' . $site->id . '">' . $CB_res . '</a></td><td><a href="index.php/admin/home/att_report/3/' . $site->id . '">' . $not_res . '</a></td><td><a href="index.php/admin/home/att_report/4/' . $site->id . '">' . $CB_res . '</a></td></tr>';

我正在显示这个循环来调用这样的函数：

#Load packages
library(ggplot2)
library(sp)

#create spatial data
lon<-rnorm(10000,mean = 15,sd=1)
lat<-rnorm(10000,mean=45,sd=1)
data <-cbind.data.frame(lon,lat)

#create the heatmap
heatmap <- ggplot(data,aes(x=lon,y=lat))+  stat_density2d(data=data,
                                      aes(x=lon, y=lat,  fill=..level..,
                                        alpha=..level..), geom="polygon")

# build the heatmap without plotting it
gb_heat <- ggplot_build(heatmap)


# extract the polygon specifications
gb_heat_dat <- gb_heat$data[[1]]

# make some polygons!
SpatialPolygons(lapply(unique(gb_heat_dat$group), function(x) {
pts <- gb_heat_dat[gb_heat_dat$group == x,]
Polygons(list(Polygon(as.matrix(data.frame(x=pts$x, y=pts$y)))), as.character(x))
})) -> polys



# plot them
plot(polys)

Answer 1

你必须在你的SQL中使用案例

CASE
    WHEN Responded== 3 THEN 1
    ELSE 0 
end

或者你必须在你的sql中使用if else并使用count关键字获取总礼物

$sql = "SELECT sch.start_date,COUNT(IF(reply_status_id = '1', 1,0)) AS `presentcnt`,COUNT(IF(reply_status_id = '0', 1,0)) AS `not_res  FROM #__schedule AS sch WHERE sch.start_date like '%".$y."%' and sch.site_id='".$site_id."' order by sch.start_date ASC";

在foreach循环中为考勤表汇总相同日期的多个值

1 个答案: