Question

我有以下数组：

$avail = array($this->item->extraFields->RoomONEDateAvailable->value, $this->item->extraFields->RoomTWODateAvailable->value, $this->item->extraFields->RoomTHREEDateAvailable->value, $this->item->extraFields->RoomFOURDateAvailable->value, $this->item->extraFields->RoomFIVEDateAvailable->value, $this->item->extraFields->RoomSIXDateAvailable->value, $this->item->extraFields->RoomSEVENDateAvailable->value, $this->item->extraFields->RoomEIGHTDateAvailable->value, $this->item->extraFields->RoomNINEDateAvailable->value, $this->item->extraFields->RoomTENDateAvailable->value);

这些是实际值：

Array ( [0] => Thursday, 01 January 1970 [1] => Thursday, 03 September 2015 [2] => Thursday, 01 January 1970 [3] => Thursday, 01 January 1970 [4] => Thursday, 01 January 1970 [5] => Thursday, 01 January 1970 [6] => Thursday, 01 January 1970 [7] => Thursday, 01 January 1970 [8] => Thursday, 01 January 1970 [9] => Thursday, 01 January 1970 )

我需要删除所有＆＃39;星期四，1970年1月1日＆＃39;数组中的日期，因此它只包含有效日期，我该怎么办呢？

Answer 1

尝试：

$avail = array_diff($avail, array('Thursday, 01 January 1970'));

Answer 2

您无需重建阵列，可以使用unset() [reference]删除阵列条目。
更新：此处不需要引用，您可以直接使用相应的数组：

foreach($avail as $key => $val)
{
    if($val == "Thursday, 01, January 1970")
        unset($avail[$key]);
}

var_dump($avail);

这是经过测试的，应该适合你。

Answer 3

您可以使用array_keys（）函数，添加搜索特定值的选项，如下所示：

array_keys($array, "Thursday, 01 January 1970")

它将返回一个匹配索引数组，您应该从原始数组中取消设置。

php数组过滤掉旧日期

3 个答案: