Question

我有一个包含航班号和门号的java对象列表：

public class Flight {
  public String flightNumber;
  public String gateNumber;
}

出于这个问题的目的，我的列表包含具有以下航班号和门号的对象：

"AA123"  "10"
"BB789"  "11"
"BB124"  "10"
"AA456"  "12"

我知道如果我想在门10选择所有对象，我可以使用以下JXPath表达式（可以工作）：

.[gateNumber = "10"]

我需要做的是选择10号门的所有物品，其航班号以＆＃34; AA＆＃34;开头。

我已尝试过以下操作，但没有一个能够正常工作：

.[gateNumber = "10" and flightNumber.startsWith("AA")]
.[gateNumber = "10" and flightNumber.substring(0, 2) = "AA"]
.[gateNumber = "10" and substring(flightNumber, 0, 2) = "AA"]
.[gateNumber = "10" and substring($flightNumber, 0, 2) = "AA"]

我的JXPath表达式应该是什么？如果不编写自定义扩展名，它甚至可以吗？

Answer 1

I could not find a way using native JXPath, so in the end I had to develop an extension that returned true if the contents of the first string parameter started with the contents of the second string parameter:

.[gateNumber = "10" and utils:startsWith(flightNumber, "AA")]

Edit

I haven't tried it, but apparently JXPath supports the starts-with() function from XPath.

如何在JXPath表达式中使用字符串的子字符串

1 个答案: