Question

这是我的示例路径：＆＃39; c：\ Data \ 2015-08-01＆＃39;

目前我在一（1）个特定日期收到所有文件，但我的目标是获取日期范围为file folder的文件。示例是2015-08-01到2015-08-05＆＃39;就像MySQL中的BETWEEN查询

一样

import os
import os.path
import tempfile

dateStart = '2015-08-01'
dateEnd = '2015-08-05'

year = dateStart[0:4]
yearMonth = year + '_' + dateStart[5:7] 

pathDir = 'c:\\Data'
date_folder = pathDir  + '\\' + dateStart

count = 0
for filefolder in os.listdir(date_folder):
     filefolder = date_folder + "\\" + filefolder
        for file in os.listdir(filefolder): 
            if "txt" in file:
                filename = filefolder + "\\" + file 
                    print filename
                    #Output of this, is all text files for this date only '2015-08-01'

我很难循环播放日期范围的文件，例如＆＃39; 2015年8月1日＆＃39;到2015-08-05＆＃39;。怎么做？

请注意，我的日期后面有一个文件夹，文本文件位于最后一个文件夹中。并且包含在该文件夹上的文本文件是我的要点。所以从我的旧代码中我使用了这个：filefolder = date_folder +＆＃34; \＆＃34; + filefolder仅在1个日期获取文本。

以下是我的示例实际路径数据：

 \\10.81.67.162\DLCx Logs\DLCx02\2015\2015_08\2015-08-01\Folder\data.text

如果我将从2015-08-01到2015-08-01获得该范围。这将是输出：

 \\10.81.67.162\DLCx Logs\DLCx02\2015\2015_08\2015-08-01\Folder\data.text
 \\10.81.67.162\DLCx Logs\DLCx02\2015\2015_08\2015-08-02\Folder\data.text
 \\10.81.67.162\DLCx Logs\DLCx02\2015\2015_08\2015-08-03\Folder\data.text
 \\10.81.67.162\DLCx Logs\DLCx02\2015\2015_08\2015-08-04\Folder\data.text
 \\10.81.67.162\DLCx Logs\DLCx02\2015\2015_08\2015-08-05\Folder\data.text

Answer 1

这是我的方法：从单独的年，月，日开始并建立日期：

import glob
import os


pattern = os.path.join(r'C:\Data', '{}-{:02}-{:02}', '*', '*.txt')

year, month = 2015, 8
start_day, end_day = 1, 5

for day in range(start_day, end_day + 1):
    wildcard = pattern.format(year, month, day)
    for filename in glob.glob(wildcard):
        print filename

Answer 2

datetime模块进行日期算术，比较，以及相对容易地将它们转换为字符串或从字符串转换。

以下是它可以用来做你想要完成的事情（至少根据你最近的评论）：

from datetime import datetime, timedelta
from glob import glob
from os import path

DATE_FORMAT = '%Y-%m-%d'
SUBFOLDER_PATH_FORMAT = r'%Y\%Y_%m\%Y-%m-%d\Folder'
pathDir = r'\\10.81.67.162\DLCx Logs\DLCx02'
dateStart = '2015-08-01'
dateEnd = '2015-09-01'
start_date = datetime.strptime(dateStart, DATE_FORMAT).date()
end_date = datetime.strptime(dateEnd, DATE_FORMAT).date()
delta_one_day = timedelta(days=1)

date = start_date
while date <= end_date:
    subfolder_path = date.strftime(SUBFOLDER_PATH_FORMAT)
    data_folder = path.join(pathDir, subfolder_path)
    if path.isdir(data_folder):
        for filename in glob(os.path.join(data_folder, '*.txt')):
            print filename
    date += delta_one_day

Answer 3

最简单的方法是将日期转换为日期对象。然后你可以比较它们。见下面的例子：

#!/usr/bin/python

import os
import os.path
import tempfile
import datetime
import re

dateStart = '2015-08-03'
dateEnd = '2015-08-05'

# helper function to convert date strings to date objects
def make_dt(ds):
    return datetime.date(int(ds[0:4]), int(ds[5:7]), int(ds[8:10]))

# convert date string to date object
dt_start = make_dt(dateStart)
dt_end = make_dt(dateEnd)

pathDir = '.'

if __name__ == "__main__":

    for folder in os.listdir(pathDir):
        # only folders that match date format yyyy-mm-dd
        if re.match("[0-9]{4}-[0-9]{2}-[0-9]{2}", folder):
            # convert folder name to date object
            dt_folder = make_dt(folder)
            if (dt_folder <= dt_end) and (dt_folder >= dt_start):
                print "folder %s is between start [%s] and end [%s]" % (folder, dateStart, dateEnd)

从当前目录的日期范围获取文件

3 个答案: