Question

我有按日期和24小时间隔的帐号表

ACCT＃;日期; hour1，hour2，hour3 ...... hour24

每个帐户可能有多达365天＃我希望找到所有间隔的平均值以及每个帐号的最大间隔＃。我试图添加样本数据，但因为这是我的第一篇文章，我无法附加它（需要+10个帖子） -

＆＃34; CUSTOMER_NUMBER＆＃34; ＆＃34;日期＆＃34; ＆＃34; est_hb_0000＆＃34; ＆＃34; est_hb_0100＆＃34; ＆＃34; est_hb_0200＆＃34; ＆＃34; est_hb_0300＆＃34; ＆＃34; est_hb_0400＆＃34; ＆＃34; est_hb_0500＆＃34; ＆＃34; est_hb_0600＆＃34; ＆＃34; est_hb_0700＆＃34; ＆＃34; est_hb_0800＆＃34; ＆＃34; est_hb_0900＆＃34; ＆＃34; est_hb_1000＆＃34; ＆＃34; est_hb_1100＆＃34; ＆＃34; est_hb_1200＆＃34; ＆＃34; est_hb_1300＆＃34; ＆＃34; est_hb_1400＆＃34; ＆＃34; est_hb_1500＆＃34; ＆＃34; est_hb_1600＆＃34; ＆＃34; est_hb_1700＆＃34; ＆＃34; est_hb_1800＆＃34; ＆＃34; est_hb_1900＆＃34; ＆＃34; est_hb_2000＆＃34; ＆＃34; est_hb_2100＆＃34; ＆＃34; est_hb_2200＆＃34; ＆＃34; est_hb_2300＆＃34;

提前感谢您的帮助

Answer 1

在重新构建并填充表后，此SQL应该会让您关闭。

Select Customer, Date, HourOfDay, NumAccts
From ActivityStats
Where Customer = 'zzz'
  and Date = 'Dt'
  and RowNumber < 11
Order By NumAccts Desc

PL SQL - 新手 - MAX fron表和平均值

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