Question

我们有一个使用Spring OAuth2的其他API。用户通过身份验证后，所有JSON响应都采用以下格式：

{"code" : 12345, "data" : "..." }

但是，身份验证失败的JSON响应与上述格式不一致，因为它由Spring处理。

例如，如果凭据不正确，客户端就会获得带有JSON响应的HTTP状态代码400如下：

{"error": "invalid_grant", "error_description": "Bad credentials" }

如果用户帐户被锁定，客户端将获得带有JSON响应的HTTP状态代码400，如下所示

{"error":"invalid_grant","error_description":"User account is locked"}

所有这一切都是因为Spring TokenEndpoint.handleException（）正在处理与/ oauth / token相关的异常

我想将OAuth2失败的JSON响应更改为遵循第一种格式。

这是我迄今为止尝试过的，但没有成功：

使用具有最高优先级顺序的ControllerAdvice＆amp;使用@ExceptionHandler描述here
按照here
实现ExceptionMapper
添加了一个新的ObjectMapper，扩展了StdSerializer。虽然我的objectmapper已初始化，但它不用于序列化异常。也许是因为Spring直接调用MappingJackson2HttpMessageConverter而且我的应用程序中似乎有这个类的几个实例。

任何上述方法或新方法的任何帮助都将受到高度赞赏。

我没有尝试this方法，因为我无法更改现有客户端的上下文路径。

Answer 1

我遇到了完全相同的问题并最终解决了问题。我使用一个自定义的ExceptionHandlerExceptionResolver类作为解析器，它覆盖了下面代码中显示的方法 getExceptionHandler ，然后再次使用具有最高优先级顺序的@ControllerAdvice，最后它可以工作。

public class MyExceptionHandlerExceptionResolver extends ExceptionHandlerExceptionResolver {
private Map<ControllerAdviceBean, ExceptionHandlerMethodResolver> exceptionHandlerAdviceCache = null;

@Override
protected ServletInvocableHandlerMethod getExceptionHandlerMethod(HandlerMethod handlerMethod, Exception exception) {
    Class<?> handlerType = (handlerMethod != null ? handlerMethod.getBeanType() : null);
    List<ControllerAdviceBean> adviceBeans = ControllerAdviceBean.findAnnotatedBeans(getApplicationContext());
    if (exceptionHandlerAdviceCache==null){
        exceptionHandlerAdviceCache = new LinkedHashMap<ControllerAdviceBean, ExceptionHandlerMethodResolver>();
        for (ControllerAdviceBean adviceBean:adviceBeans){
            ExceptionHandlerMethodResolver resolver = new ExceptionHandlerMethodResolver(adviceBean.getBeanType());
            exceptionHandlerAdviceCache.put(adviceBean, resolver);
        }
    }
    for (Map.Entry<ControllerAdviceBean, ExceptionHandlerMethodResolver> entry : this.exceptionHandlerAdviceCache.entrySet()) {
        if (entry.getKey().isApplicableToBeanType(handlerType)) {
            ExceptionHandlerMethodResolver resolver = entry.getValue();
            Method method = resolver.resolveMethod(exception);
            if (method != null) {
                return new ServletInvocableHandlerMethod(entry.getKey().resolveBean(), method);
            }
        }
    }
    return null;
}
}

在configure

中使用MyExceptionHandlerExceptionResolver类

@EnableWebMvc
@Configuration
public class WebMVCConfiguration extends WebMvcConfigurationSupport {
@Bean
public ExceptionHandlerExceptionResolver handlerExceptionResolver() {
    MyExceptionHandlerExceptionResolver exceptionResolver = new MyExceptionHandlerExceptionResolver();
    exceptionResolver.setOrder(0);
    exceptionResolver.setMessageConverters(messageConverters());
    return exceptionResolver;
}

private MappingJackson2HttpMessageConverter jsonHttpMessageConverter() {
    return new MappingJackson2HttpMessageConverter();
}

private List<HttpMessageConverter<?>> messageConverters() {
    List<HttpMessageConverter<?>> messageConverters = new ArrayList<>();
    messageConverters.add(jsonHttpMessageConverter());
    return messageConverters;
}
}

Answer 2

如果要处理身份验证过程，可以设置自己的自定义身份验证管理器

<oauth:authorization-server
    client-details-service-ref="clientDetails" token-services-ref="tokenServices"
    user-approval-handler-ref="userApprovalHandler">
    <oauth:authorization-code />
    <oauth:implicit />
    <oauth:refresh-token />
    <oauth:client-credentials />
    <oauth:password authentication-manager-ref="customAuthenticationManager" />
</oauth:authorization-server>

<authentication-manager id="customAuthenticationManager"
    xmlns="http://www.springframework.org/schema/security">
    <authentication-provider ref="customAuthenticationProvider" />
</authentication-manager>

<bean id="customAuthenticationProvider"
    class="com.any.CustomAuthenticationProvider">
</bean>

创建实现AuthenticationProvider

的自定义身份验证提供程序

public class UserAuthenticationProvider implements AuthenticationProvider {

    @Override
    public Authentication authenticate(Authentication authentication) throws AuthenticationException {

        UsernamePasswordAuthenticationToken auth = (UsernamePasswordAuthenticationToken) authentication;
        String username = auth.getName();
        String password = token.getCredentials().toString();
        User user = userService.loadByUsername(username);
        if(user.isLocked){
            throw new UserLockedException("User is locked");
        }
        if(another.something.bad.happened){
            throw new AnotherSomethingBadHappenedException("Error");
        }

        // setup authorities
        //...

        return new UsernamePasswordAuthenticationToken(user, password, authorities);
    }


}

现在您有了自己的异常，并且通过使用ExceptionMapper，您可以将身份验证过程中抛出的异常转换为自定义响应消息。

您可以通过创建扩展ApprovalStoreUserApprovalHandler

的自定义类，在授权流程上创建另一个自定义项

public class CustomUserApprovalHandler extends ApprovalStoreUserApprovalHandler {

    // stripped

    @Override
    public AuthorizationRequest checkForPreApproval(AuthorizationRequest authorizationRequest,
            Authentication userAuthentication) {

        ClientDetails client = clientDetailsService
                            .loadClientByClientId(authorizationRequest.getClientId());
        // here, you have the client and the user
        // you can do any checking here and throw any exception
        authorizationRequest.setApproved(approved);
        return authorizationRequest;
    }
}

为该类创建bean定义

<bean id="userApprovalHandler"
    class="com.any.CustomUserApprovalHandler">
        <property name="approvalStore" ref="approvalStore" />
        <property name="requestFactory" ref="oAuth2RequestFactory" />
        <property name="clientDetailsService" ref="clientDetails" />
        <property name="useApprovalStore" value="true" />
    </bean>

如何包装OAuth2异常？

2 个答案: