我创建了一个VBA函数=cellrange(some inputs here)
,它产生一个数组(即$AD$3:$AP$346
)
在这个例子中,我使用以下公式来获得矩阵:=MMULT(TRANSPOSE($AD$3:$AP$345),$AD$3:$AP$345)
并得到正确的答案。
当我使用我的VBA功能时:
=MMULT(TRANSPOSE(INDIRECT(cellrange(A3,"all",COLUMN(AD2)-1,COLUMN(AP2)-1))),INDIRECT(cellrange(A3,"all",COLUMN(AD2)-1,COLUMN(AP2)-1)))
问题:为什么我会收到错误,如何修复?
P.S。我之前已多次成功使用此功能,但不在=MMULT()
VBA功能代码: [据我所知,此处没有任何错误,但我提供了参考资料]
Option Explicit
Public Function cellrange(rDates As Range, vFilter As Variant, Optional colOffsetA As Variant, Optional colOffsetB As Variant) As String
'DESCRIPTION:
'This function takes any cell value in a row and a input: YTD, ALL, or any year (i.e. 2014, 2015) and it finds the range in which the date is situated
Dim i As Long, ndx1 As Long, ndx2 As Long, r As Range, vA As Variant, bErr As Boolean, bAll As Boolean
bErr = True
If IsDate(rDates) Then
With rDates.EntireColumn
i = rDates.Parent.Evaluate("count(" & .Address & ")")
Set r = .Cells(1 - i + rDates.Parent.Evaluate("index(" & .Address & ",match(9.9E+307," & .Address & "))").Row).Resize(i, 1)
End With
vA = r.Value
If IsMissing(colOffsetA) And IsMissing(colOffsetB) Then
colOffsetA = 0: colOffsetB = 0
End If
If IsMissing(colOffsetB) = True Then colOffsetB = colOffsetA
Select Case LCase(vFilter)
Case "all"
bErr = 0: bAll = 1
Set r = r.Range(r.Parent.Cells(1, 1 + colOffsetA), r.Parent.Cells(r.Count, 1 + colOffsetB))
Case "ytd"
For i = 1 To UBound(vA)
If ndx1 = 0 And Year(vA(i, 1)) = Year(Date) Then ndx1 = i
If vA(i, 1) <= Date Then ndx2 = i
Next
Case Else 'year
vFilter = Val(vFilter)
If vFilter Then
For i = 1 To UBound(vA)
If ndx1 = 0 And Year(vA(i, 1)) = vFilter Then ndx1 = i
If ndx1 And Year(vA(i, 1)) = vFilter Then ndx2 = i
Next
End If
End Select
If Not bAll Then If ndx1 > 0 And ndx2 > 0 Then Set r = r.Range(r.Parent.Cells(ndx1, 1 + colOffsetA), r.Parent.Cells(ndx2, 1 + colOffsetB)): bErr = False
If Not bErr Then cellrange = r.Address Else cellrange = CVErr(xlErrValue)
Else
cellrange = CVErr(xlErrValue) 'check if this is the correct error handling
End If
End Function
支持照片 SQL Fiddle Demo
答案 0 :(得分:0)
试试这个。使用NEWCELLRANGE更改cellrange函数并删除INDIRECT函数。看看它是否有效。
Public Function NEWCELLRANGE(rDates As Range, vFilter As Variant, Optional colOffsetA As Variant, Optional colOffsetB As Variant) As String
'DESCRIPTION:
'This function takes any cell value in a row and a input: YTD, ALL, or any year (i.e. 2014, 2015) and it finds the range in which the date is situated
Dim i As Long, ndx1 As Long, ndx2 As Long, r As Range, vA As Variant, bErr As Boolean, bAll As Boolean
bErr = True
If IsDate(rDates) Then
With rDates.EntireColumn
i = rDates.Parent.Evaluate("count(" & .Address & ")")
Set r = .Cells(1 - i + rDates.Parent.Evaluate("index(" & .Address & ",match(9.9E+307," & .Address & "))").Row).Resize(i, 1)
End With
vA = r.Value
If IsMissing(colOffsetA) And IsMissing(colOffsetB) Then
colOffsetA = 0: colOffsetB = 0
End If
If IsMissing(colOffsetB) = True Then colOffsetB = colOffsetA
Select Case LCase(vFilter)
Case "all"
bErr = 0: bAll = 1
Set r = r.Range(r.Parent.Cells(1, 1 + colOffsetA), r.Parent.Cells(r.Count, 1 + colOffsetB))
Case "ytd"
For i = 1 To UBound(vA)
If ndx1 = 0 And Year(vA(i, 1)) = Year(Date) Then ndx1 = i
If vA(i, 1) <= Date Then ndx2 = i
Next
Case Else 'year
vFilter = Val(vFilter)
If vFilter Then
For i = 1 To UBound(vA)
If ndx1 = 0 And Year(vA(i, 1)) = vFilter Then ndx1 = i
If ndx1 And Year(vA(i, 1)) = vFilter Then ndx2 = i
Next
End If
End Select
If Not bAll Then If ndx1 > 0 And ndx2 > 0 Then Set r = r.Range(r.Parent.Cells(ndx1, 1 + colOffsetA), r.Parent.Cells(ndx2, 1 + colOffsetB)): bErr = False
If Not bErr Then NEWCELLRANGE = evaluate(r) Else NEWCELLRANGE = CVErr(xlErrValue)
Else
NEWCELLRANGE = CVErr(xlErrValue) 'check if this is the correct error handling
End If
End Function