Question

所以我有两种不同的订单表格。如果一个完成然后他们检查它只生成一个订单...

但如果他们选择添加更多产品，则会在表单中添加另一个产品..

对于第一个订单号，我希望它是随机生成的数字..

但是对于代码底部的SECOND订单号。我需要它是为第一个订单生成的相同数字。

我该怎么做？

if($row == 1) {

            $sqll = mysqli_query($con, "UPDATE BubbleGum SET pendingOrders=pendingOrders + 1 WHERE Name='".$name."'");
            $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type', '$amount', '$equipment', 'THIS NUMBER NEEDS TO BE RANDOM')");

        } else {

            $sql = mysqli_query($con, "INSERT INTO Bubblegum (BrainID, name, street, city, state, zip, height, weight) VALUES ('', '$name', '$street', '$city', '$state', '$zip', '$height', '$weight')");
            $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type', '$amount', '$equipment', '')");
        }


    if(isset($_SESSION['more'])) {

        $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type2', '$amount2', '$equipment2', 'THIS NUMBER NEEDS TO BE THE SAME RANDOM NUMBER AS ABOVE')");

    }
}

更新

如果我按照建议行事。然后它只在我的mysql数据库中添加一个条目......它不会在底部添加条目。

$random = rand (1 , 10);


while($roww = mysqli_fetch_array($query)) {

        //count rows, If exist, then username exist
        $row = mysqli_num_rows($query);
        $brain = $roww['BrainID'];
        if($row == 1) {

            $sqll = mysqli_query($con, "UPDATE BubbleGum SET pendingOrders=pendingOrders + 1 WHERE Name='".$name."'");
            $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type', '$amount', '$equipment', '$random')");

        } else {

            $sql = mysqli_query($con, "INSERT INTO BubbleGum (BrainID, name, street, city, state, zip, height, weight) VALUES ('', '$name', '$street', '$city', '$state', '$zip', '$height', '$weight')");
            $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type', '$amount', '$equipment', '$random')");
        }


        if(isset($_SESSION['more'])) {

            $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type2', '$amount2', '$equipment2', '$random')");

        }
    }

Answer 1

如评论中所述，只需生成if语句范围之外的数字，例如：

$random = rand (1 , 10);

if($row == 1) {

        $sqll = mysqli_query($con, "UPDATE BubbleGum SET pendingOrders=pendingOrders + 1 WHERE Name='".$name."'");
        $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type', '$amount', '$equipment', $random)");

    } else {

        $sql = mysqli_query($con, "INSERT INTO Bubblegum (BrainID, name, street, city, state, zip, height, weight) VALUES ('', '$name', '$street', '$city', '$state', '$zip', '$height', '$weight')");
        $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type', '$amount', '$equipment', '')");
    }


if(isset($_SESSION['more'])) {

    $sqli = mysqli_query($conn, "INSERT INTO Pending (BrainID, name, Type, amount, equipment, orderNumber) VALUES ('$brain', '$name', '$type2', '$amount2', '$equipment2', $random)");

}

}

在两个不同的位置获取SAME随机生成的值

1 个答案: