Python：Matplotlib：matplotlib中

Question

我想从多个来源读取数据并将它们绘制在彼此之上。我需要绘制它们的方式是在底部标记一个x-axis，其他的应该与相同的x-axis对齐，无论哪个点可用。

以下是问题的一个示例：

import matplotlib.pylab as plt
import random
import matplotlib.gridspec as gridspec

random.seed(20)

#create x-axis of my data
x1 = range(0,10) #different range than the next one
x2 = range(1,9)

#create data (just random data corresponding the x1,x2)
data1 = [random.random() for i in x1]
data2 = [random.random()*1000 for i in x2]

gs = gridspec.GridSpec(2,1)
fig = plt.figure()

#first plot
ax = fig.add_subplot(gs[0])
ax.plot(x1,data1)
ax.set_ylabel(r'Label One', size =16)
ax.get_yaxis().set_label_coords(-0.1,0.5)
plt.tick_params(
    axis='x',          # changes apply to the x-axis
    labelbottom='off') # labels along the bottom edge are off

#second plot
ax = fig.add_subplot(gs[1])
ax.plot(x2,data2)
ax.set_ylabel(r'Label Two', size =16)
ax.get_yaxis().set_label_coords(-0.1,0.5)

plt.show()

这会产生图：

请注意，上方情节x-axis与下方情节x-axis不匹配。

我需要所有图表彼此匹配，并将较小图表中没有数据的区域留空。这可以实现吗？

如果您需要任何其他信息，请询问。

Answer 1

将sharex参数用于add_subplot()

import matplotlib.pylab as plt
import random
import matplotlib.gridspec as gridspec

random.seed(20)

#create x-axis of my data
x1 = range(0,10) #different range than the next one
x2 = range(1,9)

#create data (just random data corresponding the x1,x2)
data1 = [random.random() for i in x1]
data2 = [random.random()*1000 for i in x2]

gs = gridspec.GridSpec(2,1)
fig = plt.figure()

#first plot
ax = fig.add_subplot(gs[0])
ax.plot(x1,data1)
ax.set_ylabel(r'Label One', size =16)
ax.get_yaxis().set_label_coords(-0.1,0.5)
plt.tick_params(
    axis='x',          # changes apply to the x-axis
    labelbottom='off') # labels along the bottom edge are off

#second plot
ax = fig.add_subplot(gs[1], sharex=ax)
ax.plot(x2,data2)
ax.set_ylabel(r'Label Two', size =16)
ax.get_yaxis().set_label_coords(-0.1,0.5)

plt.show()