使用数组函数php的next（）和prev（）位置

Question

我的代码如下，

<?php
$people = array("patrick", "wumbo", "wambo", "Peter", "Joe", "Glenn", "Cleveland");

echo current($people) . "<br>";
echo next($people) . "<br>";
echo prev($people);
?>

我的问题是，如果我想当前的位置是“乔”，如何显示我之前的所有位置以及我的所有下一个位置？

输出：

my prev = *patrick wumbo wambo Peter*

my next = *Glenn Cleveland*

更新问题

<?php
$a = "My brother see the moon";
$b = explode(" ",preg_replace("/(\.|\"|,|;|\(|\)|'|)+?/i","",$a));
for($ulangKata=0;$ulangKata<count($b);$ulangKata++)
            {
            $huruf_kecil = strtolower($a);
            $fungsi_replace = preg_replace("/(\.|\"|,|;|\(|\)|'|)+?/i","",$huruf_kecil);
            $pecah_untuk_kata = explode(" ",$fungsi_replace);
            $pecah_kata = $pecah_untuk_kata[$ulangKata];
            echo "kata ke - ".$ulangKata." ".$b[$ulangKata]."<br>"; 
            }
            echo "<br>";
            for($ulangKata=0;$ulangKata<count($b);$ulangKata++)
            {
            echo $b[$ulangKata]."<br>";
            }
?>

我希望看到像

这样的输出

Subject : My brother
Predicate : see
Object : the moon

我已经尝试过但从昨晚开始就不知道了。

Answer 1

这样的东西？

TextResource

<强>输出：

    $current= "Joe";

    $people = array("patrick", "wumbo", "wambo", "Peter", "Joe", "Glenn", "Cleveland");
    $pos    = array_search($current, $people);

    foreach($people as $key => $value) {

        if($key < $pos) {

            $prev[] = $value;

        } elseif($key > $pos) {

            $next[] = $value;

        }

    }

    foreach($prev as $item) {
        echo "$item ";
    }
    echo "<br />";
    foreach($next as $item) {
        echo "$item ";
    }

更新2

patrick wumbo wambo Peter 
Glenn Cleveland 

<强>输出：

Answer 2

通过array_slice

轻松实现

$key=array_search("Joe",$people);
echo "Current:".$people[$key] . "\n" .
     "Prev:".implode(",", array_slice($people, 0, $key)) . "\n" .
     "Next:".implode(",", array_slice($people, $key+1));

Answer 3

试试这个......

<?php
$people = array("patrick", "wumbo", "wambo", "Peter", "Joe", "Glenn", "Cleveland");


$key=array_search("Joe",$people);
$next=array();
$prev=array();
for($i=$key+1;$i<count($people);$i++)
{
$next[]=$people[$i];
}

for($i=$key-1;$i >0;$i--)
{
$prev[]=$people[$i];
}

echo "Current:".$people[$key];
 echo "</br>";
echo "Next:".implode(",",$next);
 echo "</br>";
echo "prev:".implode(",",$prev);
?>

结果：

Current:Joe
Next:Glenn,Cleveland
prev:Peter,wambo wumbo

Answer 4

感谢所有人的支持，

如果我有一个像下面这样的字符串

$text = "Brother see the moon";

我签署的代码“看到”为动词，

在“看到”主题

之前的所有数组

以及“看到”对象

之后的所有数组