Question

我正在尝试使用php在我的本地数据库中创建临时表。它不会创建标题，也不会给出错误。我使用DESC temp检查，它没有显示表的结构。这是我的代码：

<?php
 error_reporting(E_ALL);
 ini_set('display_errors', 1);
 $hostname = "localhost"; 
 $username = "root";
 $password = "";
 $database = "autosearch";

 //connection to the database
 $dbhandle = mysqli_connect($hostname, $username, $password);
 $db = mysqli_select_db($dbhandle, $database) or die("Unable to connect to MySQL");
 //echo "Connected to MySQL<br>";

 $query_createTemporaryTable = "CREATE TEMPORARY TABLE #temp(temp_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY, 
                                                       ArtistName VARCHAR(20), NAMEOfTheDVD VARCHAR(30)"; 

 $result_createtemptable = mysqli_query($dbhandle, $query_createTemporaryTable);

 $query_insertintotable = "INSERT INTO temp (ArtistName, NAMEOfTheDVD) 
                                VALUES ('R', 'SHAWooSHANK')";

 $result_insertintotable = mysqli_query($dbhandle, $query_insertintotable) or die(mysqli_error($dbhandle));

 $query_selecttemptable = "SELECT ArtistName,NAMEOfTheDVD FROM temp";

 $result_selecttemptable = mysqli_query( $query_selecttemptable,$dbhandle) or die(mysqli_error());



 while($row_selecttemptable = mysqli_fetch_array($result_selecttemptable)){
  echo $row_selecttemptable;

 }
 $delete_temptable = "DROP TABLE 'temp'";
 $result_temptable = mysqli_query($delete_temptable, $dbhandle) or die(mysqli_error());
 mysqli_close();

?>

Answer 1

这里有几个错误

首先你有一个点而不是一个逗号作为temp_id之后的分隔符，它不能编译。此外，列列表中有3列，数据列表中只有2列。实际上你不需要传递temp_id，因为它是一个AutoIncrement列。所以将此行更改为

$query_insertintotable = "INSERT INTO temp (ArtistName, NAMEOfTheDVD) 
                                    VALUES ('R', 'SHAWooSHANK')";

Answer 2

以下是修复错误的代码，临时表重命名为temp_artist。

这些都是小错误。我建议您在开发PHP环境中设置最高级别的错误检查。

在PHP中使用之前，我还检查所有SQL代码是否都可以在IDE中运行。

错误：

create table statement

没有关闭'）'
$ dbHandle应该是mysqli_query语句中的第一个参数。
drop语句中的表名应该有反引号而不是引号。
'echo'语句在没有转换的情况下不显示array。

代码：

<?php
 error_reporting(E_ALL);
 ini_set('display_errors', 1);

 $hostname = "localhost";
 $username = "test";
 $password = "test";
 $database = "testmysql";

 //connection to the database
 $dbhandle = mysqli_connect($hostname, $username, $password);
 $db = mysqli_select_db($dbhandle, $database) or die("Unable to connect to MySQL");
 //echo "Connected to MySQL<br>";

 $query_createTemporaryTable = "CREATE TEMPORARY TABLE `temp_artist` (temp_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
                                                       ArtistName VARCHAR(20), NAMEOfTheDVD VARCHAR(30))";

 $result_createtemptable = mysqli_query($dbhandle, $query_createTemporaryTable);

 $query_insertintotable = "INSERT INTO `temp_artist` (ArtistName, NAMEOfTheDVD)
                                VALUES ('R', 'SHAWooSHANK')";

 $result_insertintotable = mysqli_query($dbhandle, $query_insertintotable) or die(mysqli_error($dbhandle));

 $query_selecttemptable = "SELECT ArtistName, NAMEOfTheDVD FROM `temp_artist`";

 $result_selecttemptable = mysqli_query($dbhandle, $query_selecttemptable) or die(mysqli_error());

 while($row_selecttemptable = mysqli_fetch_array($result_selecttemptable)){
    echo $row_selecttemptable['ArtistName'], ' - ',
         $row_selecttemptable['NAMEOfTheDVD'], '<br />';
 }

 $delete_temptable = "DROP TABLE `temp_artist`";
 $result_temptable = mysqli_query($dbhandle, $delete_temptable) or die(mysqli_error());
 mysqli_close($dbhandle);

临时表使用PHP不起作用

2 个答案: