Question

你好我有一个快速的应用程序，我每次触摸都开始调用一个函数，但我不希望在用户滑动时调用touchesBegan。我怎么能避免这个？

触动开始了：

/((?:[^=,]+)=(?:[^=]+)),/g

滑动：

{{1}}

此外，我不想做任何接触结束，因为这会增加我不能拥有的延迟

Answer 1

让你的UIViewController查看一个自定义类并处理这些触摸 - 它们应该以你尝试的方式接收，但只能在UIView类本身中接收。

Answer 2

如果要将滑动与触摸分开，可以使用delaysTouchesBegan方法轻松完成，例如：

        let swipeRight:UISwipeGestureRecognizer = UISwipeGestureRecognizer(target: self, action: Selector("swipedRight:"))
        swipeRight.direction = .Right
        swipeRight.cancelsTouchesInView = true
        swipeRight.delaysTouchesBegan = true
        view.addGestureRecognizer(swipeRight)


        let swipeLeft:UISwipeGestureRecognizer = UISwipeGestureRecognizer(target: self, action: Selector("swipedLeft:"))
        swipeLeft.direction = .Left
        swipeLeft.cancelsTouchesInView = true
        swipeLeft.delaysTouchesBegan = true
        view.addGestureRecognizer(swipeLeft)


        let swipeUp:UISwipeGestureRecognizer = UISwipeGestureRecognizer(target: self, action: Selector("swipedUp:"))
        swipeUp.direction = .Up
        swipeUp.cancelsTouchesInView = true
        swipeUp.delaysTouchesBegan = true
        view.addGestureRecognizer(swipeUp)


        let swipeDown:UISwipeGestureRecognizer = UISwipeGestureRecognizer(target: self, action: Selector("swipedDown:"))
        swipeDown.direction = .Down
        swipeDown.cancelsTouchesInView = true
        swipeDown.delaysTouchesBegan = true
        view.addGestureRecognizer(swipeDown)

在viewDidLoad或didMoveToView中（如果你在spritekit场景中）

分别制作方法：

func swipedRight(sender:UISwipeGestureRecognizer){
   print("swiped right")
}

func swipedLeft(sender:UISwipeGestureRecognizer){
   print("swiped left")
}

func swipedUp(sender:UISwipeGestureRecognizer){
   print("swiped up")
}

func swipedDown(sender:UISwipeGestureRecognizer){
   print("swiped down")
}

然后，您可以使用官方委托方法控制您的触摸，例如：

override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
...// handle your touches..
}

如果滑动，Swift不会触发touchesBegan

2 个答案: