Question

我在我的应用中添加了一些额外的搜索功能 - 经过测试，在Android 4.4.2上运行良好。

刚刚将我的设备更新到5.0，这个新的搜索功能不起作用，返回一个空光标。（应用程序中的其他查询都可以在所有设备上正常工作，表明这是代码问题而不是数据问题。）

据我所知，从Android 4.4.2到Android 5.0，SQLite已从3.7.11更新到3.8.0，我希望这是此问题的原因。我看过changelog for SQLite 3.8.0并且没有任何东西可以引人注目（无论如何都是我未经训练的眼睛）。

以下是我的代码生成的问题：

SELECT
    statuses.status AS status,
    shelves.shelf_name AS shelf_name, 
    aisles.aisle_name AS aisle_name, 
    products.image_file_name_stored AS image_file_name_stored, 
    parent_companies.url AS url, 
    parent_companies.email AS email, 
    products.buy_url AS buy_url, 
    products_data.status_id AS status_id, 
    parent_companies.company_name AS company_name, 
    products.image_file_name AS image_file_name, 
    '(' || shelves.shelf_name || ')' AS suggest_text_2, 
    products._id AS suggest_intent_data_id, 
    products.product_name AS suggest_text_1, 
    parent_companies.tel AS tel, 
    products.product_name AS product_name, 
    products_data.notes AS notes, 
    products.priority AS priority, 
    products._id AS _id, 
    products_data.last_modified_on AS last_modified_on 

FROM 
    products

INNER JOIN 
    parent_companies ON products.parent_company_id = parent_companies._id

INNER JOIN 
    shelves ON products.shelf_id = shelves._id

INNER JOIN
    aisles ON shelves.aisle_id = aisles._id

INNER JOIN 
    products_data ON products._id = products_data.product_id

INNER JOIN
    statuses ON products_data.status_id = statuses._id

WHERE 
    (shelves._id = ?)

ORDER BY
    shelf_name ASC

我的selectionArgs = {"156"}。

更新

现在，为了测试，我已将selection字符串设置为null，将selectionArgs字符串[]设置为null，现在光标充满结果 - 太多，当然因为不再有WHERE条件。

所以，我的问题最终是这个......为什么让以下选择标准在Android 4.4.2（SQLite 3.7.11）中给出结果但在Android 5.0（SQLite 3.8.0）中没有结果？... < / p>

String selection = "shelves._id = ?";
String[] selectionArgs = {"156"};

...当然不是我试图将整数列（_id）与字符串（"156"）进行比较？！

更新＃2

使用有问题的查询，我介入调试器，在SQLiteQueryBuilder.java的第393行，然后sql String是......

“SELECT statuses.status AS status，shelves.shelf_name AS shelf_name， aisles.aisle_name AS aisle_name，products.image_file_name_stored AS image_file_name_stored，parent_companies.url AS url， parent_companies.email AS电子邮件，products.buy_url AS buy_url， products_data.status_id AS status_id，parent_companies.company_name AS company_name，products.image_file_name AS image_file_name，'（'|| shelves.shelf_name || '）'AS suggest_text_2，products._id AS suggest_intent_data_id，products.product_name AS suggest_text_1， parent_companies.tel AS tel，products.product_name AS product_name， products_data.notes AS notes，products.priority AS priority， products._id AS _id，products_data.last_modified_on AS last_modified_on FROM products INNER JOIN parent_companies ON products.parent_company_id = parent_companies._id INNER JOIN货架 ON products.shelf_id = shelves._id INNER JOIN aisles ON shelves.aisle_id = aisles._id INNER JOIN products_data ON products._id = products_data._id INNER JOIN状态ON products_data.status_id = statuses._id WHERE（shelves._id =？）ORDER BY shelf_name ASC“

......看起来不错。我继续使用调试器来查看它出错的地方，但当我进入db.rawQueryWithFactory()方法时，调试器似乎迷路了（它把我带到了注释行），所以我不确定实际问题可能是什么。

Answer 1

我怀疑是对的。我刚刚尝试使用此代码修改selection和selectionArgs，现在所有内容都按预期工作：

        if (selection != null && selectionArgs != null && selectionArgs.length == 1 && isNumeric(selectionArgs[0])) {
            selection = selection.replace("?", selectionArgs[0]); // e.g., changes "shelves._id = ?" to "shelves._id = 156"
            selectionArgs = null; // e.g., changes {"156"} to null
        }

SQLite查询不再适用于Android 5.0

1 个答案: