Question

我正在阅读的文件样本

011084,31.0581,-87.0547,  25.9 AL BREWTON 3 SSE     
012813,30.5467,-87.8808,   7.0 AL FAIRHOPE 2 NE     
013160,32.8347,-88.1342,  38.1 AL GAINESVILLE LOCK     
013511,32.7017,-87.5808,  67.1 AL GREENSBORO     
013816,31.8700,-86.2542, 132.0 AL HIGHLAND HOME     
015749,34.7442,-87.5997, 164.6 AL MUSCLE SHOALS AP     
017157,34.1736,-86.8133, 243.8 AL SAINT BERNARD     
017304,34.6736,-86.0536, 187.5 AL SCOTTSBORO

GAWK代码

#!/bin/gawk

BEGIN{
FS=",";
OFS=",";
}

{
print $1,$2,$3,$4
station=""$1 #Forces to be string

#Save latitude 
stationInfo[station][lat]=$2
print "lat",stationInfo[station][lat]

#Save longitude
stationInfo[station][lon]=$3
print "lon",stationInfo[station][lon]

#Now try printing the latitude again
#It will return the value of the longitude instead
print "lat",stationInfo[station][lat]

print "---------------"
}

示例输出

011084,31.0581,-87.0547,  25.9 AL BREWTON 3 SSE                  
lat,31.0581
lon,-87.0547
lat,-87.0547
---------------
012813,30.5467,-87.8808,   7.0 AL FAIRHOPE 2 NE                  
lat,30.5467
lon,-87.8808
lat,-87.8808
---------------

由于某种原因，stationInfo[station][lat]中存储的值被经度覆盖。我对世界上正在发生的事情感到茫然。

我在Fedora 22上使用GAWK 4.1.1

Answer 1

您的问题是lon和lat是变量并评估为空字符串，因此此作业stationInfo[station][lat]=$2和stationInfo[station][lon]=$3分配给stationInfo[station]["]

您需要引用这些（和其他）行中的lat和lon来使用字符串而不是变量。

#!/bin/gawk

BEGIN{
    FS=",";
    OFS=",";
}

{
    print $1,$2,$3,$4
    station=""$1 #Forces to be string

    #Save latitude 
    stationInfo[station]["lat"]=$2
    print "lat",stationInfo[station]["lat"]

    #Save longitude
    stationInfo[station]["lon"]=$3
    print "lon",stationInfo[station]["lon"]

    #Now try printing the latitude again
    #It will return the value of the longitude instead
    print "lat",stationInfo[station]["lat"]

    print "---------------"
}

数组值被gawk覆盖

1 个答案: