在我的弹性搜索索引"人们"有以下文件:
{"name": "John", "district": 1},
{"name": "Anne", "district": 1},
{"name": "Mary", "district": 2},
{"name": "Bobby", "district": 2},
{"name": "Nick", "district": 1},
{"name": "Bob", "district": 3},
{"name": "Kenny", "district": 1}
我想获得区域为2或1的文档的结果,但最多只有2个。所以,如果以上是我的整个索引,我希望它返回:
{"name": "John", "district": 1},
{"name": "Anne", "district": 1},
{"name": "Mary", "district": 2},
{"name": "Bobby", "district": 2},
是否可以使用弹性的单个查询来实现此目的? 非常感谢你的帮助!
答案 0 :(得分:5)
这样的事情应该这样做:
GET /some_index/some_type/_search?search_type=count
{
"aggs": {
"district_1_or_2": {
"filter": {
"bool": {
"should": [
{
"term": {
"district": 1
}
},
{
"term": {
"district": 2
}
}
]
}
},
"aggs": {
"district": {
"terms": {
"field": "district",
"size": 10
},
"aggs": {
"top": {
"top_hits": {
"size": 2
}
}
}
}
}
}
}
}