Saripaar验证Android,多种形式

时间:2015-08-03 18:34:43

标签: android forms validation saripaar

我想在同一个活动(和布局)中使用saripaar验证3个表单。这会验证三种形式,但它们不会独立验证。

这个布局:

  • Form1:输入电子邮件和提交按钮。
  • Form2:输入验证码和提交按钮。
  • Form3:输入密码,密码确认和提交按钮。

我希望当你按form for form1时,只验证form1中的规则,并且对form2和form3进行相同的验证。

我有3个验证器对象,每个对象的逻辑类似。例如:

validatorEmail = new Validator(this);
editTextRecoveryEmail = (EditText) findViewById(R.id.editTextRecoveryEmail);
buttonRecoveryEmail = (Button) findViewById(R.id.buttonRecoveryEmail);

validatorEmail.setValidationListener(new ValidationListener() {

            @Override
            public void onValidationSucceeded() {
                // Enviar el email
            }

            @Override
            public void onValidationFailed(View failedView, Rule<?> failedRule) {
                String message = failedRule.getFailureMessage();
                if (failedView instanceof EditText) {
                    if (failedView.getId() == editTextRecoveryEmail.getId()) {
                        failedView.requestFocus();
                        ((EditText) failedView).setError(message);
                    }
                }
            }
        });

buttonRecoveryEmail.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                validatorEmail.validate();
            }

        });

这是我的完整活动代码:

/* Inicializamos los controles */
        editTextRecoveryEmail = (EditText) findViewById(R.id.editTextRecoveryEmail);
        editTextRecoveryCode = (EditText) findViewById(R.id.editTextRecoveryCode);
        editTextRecoveryPassword = (EditText) findViewById(R.id.editTextRecoveryPassword);
        editTextRecoveryPasswordConfirm = (EditText) findViewById(R.id.editTextRecoveryPasswordConfirm);
        buttonRecoverySubmit = (Button) findViewById(R.id.buttonRecoverySubmit);
        buttonRecoveryCode = (Button) findViewById(R.id.buttonRecoveryCode);
        buttonRecoveryEmail = (Button) findViewById(R.id.buttonRecoveryEmail);
    /* Objeto validador */
    validatorEmail = new Validator(this);
    validatorCode = new Validator(this);
    validatorSubmit = new Validator(this);

    validatorEmail.setValidationListener(new ValidationListener() {

        @Override
        public void onValidationSucceeded() {
            // Enviar el email
        }

        @Override
        public void onValidationFailed(View failedView, Rule<?> failedRule) {
            String message = failedRule.getFailureMessage();
            if (failedView instanceof EditText) {
                if (failedView.getId() == editTextRecoveryEmail.getId()) {
                    failedView.requestFocus();
                    ((EditText) failedView).setError(message);
                }
            }
        }
    });

    validatorCode.setValidationListener(new ValidationListener() {

        @Override
        public void onValidationSucceeded() {
            // Validar código
        }

        @Override
        public void onValidationFailed(View failedView, Rule<?> failedRule) {
            String message = failedRule.getFailureMessage();
            if (failedView instanceof EditText) {
                if (failedView.getId() == editTextRecoveryCode.getId()) {
                    failedView.requestFocus();
                    ((EditText) failedView).setError(message);
                }
            }

        }
    });

    validatorSubmit.setValidationListener(new ValidationListener() {

        @Override
        public void onValidationSucceeded() {
            // Validar Submit
        }

        @Override
        public void onValidationFailed(View failedView, Rule<?> failedRule) {
            String message = failedRule.getFailureMessage();
            if (failedView instanceof EditText) {
                if (failedView.getId() == editTextRecoveryPassword.getId()
                        || failedView.getId() == editTextRecoveryPasswordConfirm.getId()) {
                    failedView.requestFocus();
                    ((EditText) failedView).setError(message);
                }
            }

        }
    });

    /* Comportamiento del botón de Registro */
    buttonRecoveryEmail.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            validatorEmail.validate();
        }

    });

    /* Comportamiento del botón de Registro */
    buttonRecoveryCode.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            validatorCode.validate();
        }

    });

    /* Comportamiento del botón de Registro */
    buttonRecoverySubmit.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            validatorSubmit.validate();
        }

    });

1 个答案:

答案 0 :(得分:2)

这是一个有趣的问题。您将需要3个不同控制器类中的3个验证器来处理这种情况。

static class EmailController implements ValidationListener {

    @Email
    private EditText mEmailEditText;
    private Button mSubmitButton;

    private Context mContext;
    private Validator mValidator;

    public EmailController(@NonNull EditText emailEditText, @NonNull Button submitButton) {
        mEmailEditText = emailEditText;
        mSubmitButton = submitButton;
        mContext = emailEditText.getContext();

        mValidator = new Validator(this);
        mValidator.setValidationListener(this);

        mSubmitButton.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                validator.validate();
            }
        });
    }

    @Override
    public void onValidationSucceeded() {
        // Success...
    }

    @Override
    public void onValidationFailed(List<ValidationError> errors) {
        // Failure...
    }
}

您还需要2个以上 - 一个用于验证码,另一个用于密码。如果您希望与您的活动进行通信,请传递它或实现适当的侦听器接口。

如果可能,请考虑简化表单。