我是D3.js的新手。
用于绘制树的JS:
var json =
{
"name": "Base",
"children": [
{
"name": "Type A",
"children": [
{
"name": "Section 1",
"children": [
{"name": "Child 1"},
{"name": "Child 2"},
{"name": "Child 3"}
]
},
{
"name": "Section 2",
"children": [
{"name": "Child 1"},
{"name": "Child 2"},
{"name": "Child 3"}
]
}
]
},
{
"name": "Type B",
"children": [
{
"name": "Section 1",
"children": [
{"name": "Child 1"},
{"name": "Child 2"},
{"name": "Child 3"}
]
},
{
"name": "Section 2",
"children": [
{"name": "Child 1"},
{"name": "Child 2"},
{"name": "Child 3"}
]
}
]
}
]
};
var width = 700;
var height = 650;
var maxLabel = 150;
var duration = 500;
var radius = 5;
var i = 0;
var j = 0;
var root;
var columnAttribute ;
var tree = d3.layout.tree()
.size([height, width]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height)
.append("g")
.attr("transform", "translate(" + maxLabel + ",0)")
;
root = json;
root.x0 = height / 2;
root.y0 = 0;
root.children.forEach(collapse);
function update(source)
{
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse();
var links = tree.links(nodes);
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * maxLabel; });
// Update the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function(d){
return d.id || (d.id = ++i);
});
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter()
.append("g")
.attr("class", "node")
.attr("transform", function(d){ return "translate(" + source.y0 + "," + source.x0 + ")"; });
nodeEnter.append("circle")
.attr("r", 0)
.style("fill", function(d){
return d._children ? "lightsteelblue" : "white";
});
nodeEnter.append("text")
.attr("x", function(d){
var spacing = computeRadius(d) + 5;
return d.children || d._children ? -spacing : spacing;
})
.attr("dy", "3")
.attr("text-anchor", function(d){ return d.children || d._children ? "end" : "start"; })
.text(function(d){ return d.name; })
.style("fill-opacity", 0);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", function(d){ return computeRadius(d); })
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeUpdate.select("text").style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.select("circle").attr("r", 0);
nodeExit.select("text").style("fill-opacity", 0);
// Update the links…
var link = svg.selectAll("path.link")
.data(links, function(d){ return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d){
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
});
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d){
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d){
d.x0 = d.x;
d.y0 = d.y;
});
}
function computeRadius(d)
{
if(d.children || d._children) return radius + (radius * nbEndNodes(d) / 10);
else return radius;
}
function nbEndNodes(n)
{
nb = 0;
if(n.children){
n.children.forEach(function(c){
nb += nbEndNodes(c);
});
}
else if(n._children){
n._children.forEach(function(c){
nb += nbEndNodes(c);
});
}
else nb++;
return nb;
}
function click(d)
{
if (d.children){
d._children = d.children;
d.children = null;
}
else{
d.children = d._children;
d._children = null;
}
update(d);
}
function collapse(d){
if (d.children){
d._children = d.children;
d._children.forEach(collapse);
d.children = null;
}
}
update(root);
我希望双击columnAttribute
变量中的节点时保存节点名称。
例如,在点击名为Child 1
的节点时,它保存在columnAttribute : ["Child 1"]
中。同样,点击名为Child 2
的节点,它保存在columnAttribute : ["Child 1","Child2"]
答案 0 :(得分:2)
您可以在新创建的节点上使用双击事件(名为dblclick
):
var nodeEnter = node.enter()
.append("g")
.attr("class", "node")
.attr("transform", function(d){ return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", click)
.on("dblclick", dblClick)
在dblClick
功能中,只需添加您想要的名称或任何内容columnAttribute
:
var columnAttribute = [];
function dblClick(d) {
columnAttribute.push(d.name);
console.log(columnAttribute);
}
请参阅此fiddle