Question

我试图从我的数据库中返回一些结果，其中date_order列是1970年，但该查询还返回了2014年和2015年的日期。我尝试了几个查询，但它完全相同。< / p>

我的表

accession_id (INT),
date_order(DATE) DEFAULT '0000-00-00',
date_billed(DATE) DEFAULT '0000-00-00',
date_paid(DATE) DEFAULT '0000-00-00'

我的查询：

SELECT DISTINCT(accession_id), date_order, date_billed, date_paid FROM billing WHERE date(date_order) = '1970-01-01' AND accession_id BETWEEN '206070' AND '296715' OR '402603' AND '411626';
SELECT DISTINCT(accession_id), date_order, date_billed, date_paid FROM billing WHERE date_order = '1970-01-01' AND accession_id BETWEEN '206070' AND '296715' OR '402603' AND '411626';
SELECT DISTINCT(accession_id), date_order, date_billed, date_paid FROM billing WHERE date_order LIKE '%1970%' AND accession_id BETWEEN '206070' AND '296715' OR '402603' AND '411626';

Answer 1

您需要在第一组日期之后指定BETWEEN，并使用括号。像这样：

SELECT DISTINCT(accession_id), date_order, date_billed, date_paid FROM billing WHERE date(date_order) = '1970-01-01' AND 
(
  accession_id BETWEEN '206070' AND '296715'
  OR
  accession_id BETWEEN '402603' AND '411626'
);

现在看来，这些数字正在评估为真，并且它们已被OR化，因此您将获得所有结果。

选择日期会导致错误的结果

1 个答案: