Question

网页不会死，它只显示警告。请告诉我这段代码中的问题。谢谢。

<?php

$connect = mysql_connect('localhost','root','') || die("Error");
$selectDB = mysql_select_db('mydb') || die("Error");

$query = "SELECT * FROM user_login WHERE ID='2';";
$fetch = mysql_query($query) || die("Error");

while ($row = mysql_fetch_assoc($fetch)){ #problem is somewhere here
    echo $row['User_Name'];
    echo $row['Password'];
    echo $row['Gender'];
    echo $row['ID'];
}

?>

给出的警告是：

mysql_fetch_assoc（）期望参数1为资源，布尔值为

Answer 1

<?php
    $connect = mysql_connect('localhost','root','') || die("Error");
    $selectDB = mysql_select_db('mydb') || die("Error");

    $query = "SELECT * FROM user_login WHERE ID='2';";

    $fetch = mysql_query($query) || die("Error");
    $count = count($fetch);

    if($count>0)
    {
        while ($row = mysql_fetch_assoc($fetch))
        { #problem is somewhere here
            echo $row['User_Name'];
            echo $row['Password'];
            echo $row['Gender'];
            echo $row['ID'];
        }
    }
    else
    {
        echo 'No Item to select';
    }
?>

警告
自PHP 5.5.0起，此扩展已弃用，将来将被删除。相反，应使用MySQLi或PDO_MySQL扩展名。有关详细信息，另请参阅MySQL: choosing an API指南和相关常见问题解答。

PHP警告：mysql_fetch_assoc（）期望参数1是资源，给定布尔值

1 个答案: