[编辑2]
我很难按主题排序'它被定义为模型上的关系getter' Tag'。 主题可以包含大量标记,并希望按标记的多少主题对标记进行排序。
在我的模型/ Tag.php中:
public function getTopicCount()
{
return TopicTag::find()->where(['tag_id' => $this->id])->count();
}
在我的观点/ tag / index.php中:
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'id',
'name',
[
'attribute'=>'topicCount',
'value' => 'topicCount',
],
'created_at',
['class' => 'yii\grid\ActionColumn','template' => '{view}',],
],
]); ?>
在我的控制器/ TagController.php中:
public function actionIndex()
{
$dataProvider = new ActiveDataProvider([
'query' => Tag::find(),
'sort'=> [
'defaultOrder' => ['id'=>SORT_DESC],
'attributes' => ['id','topicCount'],
],
'pagination' => [
'pageSize' => 100,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
]);
}
在我的模型中/ TagSearch.php:
<?php
namespace common\models;
use Yii;
/**
* This is the model class for table "tags".
*
* @property integer $id
* @property string $name
* @property string $created_at
* @property string $updated_at
*/
class TagSearch extends Tag
{
public $topicCount;
/**
* @inheritdoc
*/
public function rules()
{
return [
[['topicCount'], 'safe']
];
}
public function search($params)
{
// create ActiveQuery
$query = Tag::find();
$query->joinWith(['topicCount']);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->sort->attributes['topicCount'] = [
'asc' => ['topicCount' => SORT_ASC],
'desc' => ['topicCount' => SORT_DESC],
];
if (!($this->load($params) && $this->validate())) {
return $dataProvider;
}
$query->andFilterWhere([
//... other searched attributes here
])
->andFilterWhere(['=', 'topicCount', $this->topicCount]);
return $dataProvider;
}
}
在索引视图中,我可以看到正确的topicCount:
但是点击topicCount列我得到错误:
exception 'PDOException' with message 'SQLSTATE[42703]: Undefined column: 7 ERROR: column "topicCount" does not exist
LINE 1: SELECT * FROM "tags" ORDER BY "topicCount" LIMIT 100
感谢任何指导..!
跟随卢卡斯&#39;建议,我在我的$ dataProvider中设置了我的dataProvider查询,如下所示:
'query' => $query->select(['tags.*','(select count(topic_tags.id) from topic_tags where topic_tags.tag_id=tags.id) topicCount'])->groupBy('tags.id'),
我收到了错误:
exception 'PDOException' with message 'SQLSTATE[42P01]: Undefined table: 7 ERROR: missing FROM-clause entry for table "tags"
所以我重新拟定了这样的话:
'query' => $query->from('tags')->leftJoin('topic_tags','topic_tags.tag_id = tags.id')->select(['tags.*','(select count(topic_tags.id) from topic_tags where topic_tags.tag_id=tags.id) topicCount'])->groupBy('tags.id'),
现在我得到了结果:
显然没有设置topicCount列,所以当我尝试按它排序时,它会返回错误:
exception 'PDOException' with message 'SQLSTATE[42703]: Undefined column: 7 ERROR: column "topicCount" does not exist
但是当我直接在数据库上尝试SQL时,它运行正常:
所以我认为问题在于Yii处理别名&#39; topicCount&#39;?
如果没有在Grid视图中设置topicCount,结果仍然相同。 我在下面显示我的TagSearch模型,TagController和views / tag / index视图文件:
TagSearch
<?php
namespace common\models;
use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use common\models\Tag;
/**
* TagSearch represents the model behind the search form about `common\models\Tag`.
*/
class TagSearch extends Tag
{
public $topicCount;
/**
* @inheritdoc
*/
public function rules()
{
return [
[['id', 'topicCount'], 'integer'],
[['name', 'created_at', 'updated_at', 'topicCount'], 'safe'],
];
}
/**
* @inheritdoc
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
/**
* Creates data provider instance with search query applied
*
* @param array $params
*
* @return ActiveDataProvider
*/
public function search($params)
{
$query = Tag::find();
$dataProvider = new ActiveDataProvider([
'query' => $query->from("tags")->select(["tags.*","(select count(topic_tags.id) from topic_tags where topic_tags.tag_id=tags.id) topicCount"])->groupBy("tags.id"),
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
$query->where('0=1');
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
'topicCount' => $this->topicCount,
'created_at' => $this->created_at,
'updated_at' => $this->updated_at,
]);
$query->andFilterWhere(['like', 'name', $this->name]);
return $dataProvider;
}
}
标记模型
<?php
namespace common\models;
use Yii;
/**
* This is the model class for table "tags".
*
* @property integer $id
* @property integer $topicCount
* @property string $name
* @property string $created_at
* @property string $updated_at
*/
class Tag extends \yii\db\ActiveRecord
{
public $topicCount;
/**
* @inheritdoc
*/
public static function tableName()
{
return 'tags';
}
/**
* @inheritdoc
*/
public function rules()
{
return [
[['topicCount'], 'integer'],
[['name'], 'string'],
[['created_at', 'updated_at'], 'required'],
[['created_at', 'updated_at'], 'safe']
];
}
/**
* @inheritdoc
*/
public function attributeLabels()
{
return [
'id' => 'ID',
'name' => 'Name',
'topicCount' => 'TC',
'created_at' => 'Created At',
'updated_at' => 'Updated At',
];
}
}
TagController
public function actionIndex()
{
$searchModel = new TagSearch();
$myModels = $searchModel->search([]);
return $this->render('index', [
'dataProvider' => $myModels,
]);
}
标签/索引
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'id',
'name',
'topicCount',
'created_at',
'updated_at',
['class' => 'yii\grid\ActionColumn','template' => '{view}',],
],
]); ?>
我错过了什么?
答案 0 :(得分:4)
在this wiki后解决:
因为在我的情况下我不使用SUM(&#39;金额&#39;),所以我改为以下并完美运作:
标记模型:
public function getTopicCount()
{
return $this->hasMany(TopicTag::className(), ["tag_id" => "id"])->count();
}
TagSearch模型:
$query = Tag::find();
$subQuery = TopicTag::find()->select('tag_id, COUNT(tag_id) as topic_count')->groupBy('tag_id');
$query->leftJoin(["topicSum" => $subQuery], '"topicSum".tag_id = id');
刚刚遇到生成的SQL问题:
exception 'PDOException' with message 'SQLSTATE[42P01]: Undefined table: 7 ERROR: missing FROM-clause entry for table "topicsum"
这可能是Postgres特有的问题,必须安排代码,以便生成的SQL变成这样:
SELECT COUNT(*) FROM "tags"
LEFT JOIN (SELECT "tag_id", COUNT(*) as topic_count FROM "topic_tags" GROUP BY "tag_id") "topicSum"
ON "topicSum".tag_id = id
请注意"topicSum".tag_id
部分中的双引号。
希望这可能对在Yii2上使用Postgres的人有所帮助。
答案 1 :(得分:1)
您应该将查询更改为分组并选择计数而不是使用关系。
$query->groupBy('tags.id')->select(['tags.*','(select count(topic_tag.id) from topic_tag where topic_tag.tag.id=tags.id) topicCount']);
这将在查询中添加topicCount
作为结果对象,这将使其行为像普通列一样。
另外作为旁注,对于在Yii2中处理关系的方法,它必须返回ActiveQuery
个对象。您的getTopicCount()
将计数作为int而不是查询返回,因此Yii2不会将其视为关系。
答案 2 :(得分:0)
基于this Wiki和@ arogachev的回答。我将select
属性设置为获取标记计数
public function search($params)
{
$query = SomeModels::find()
->select('subQueryName.field_count, someModels.*');
// ....
因此它会像这样SELECT subQuery.field_count, someModels.*
...
在视图(网格),
[
'attribute'=> 'field_count',
],
谢谢@arogachev,你救了我:)。
答案 3 :(得分:0)
轻量级解决方案只是在PostgreSQL中重新view
并使用gii
生成器生成模型,使用模型和顺序&amp;找工作。
更新&amp;删除使用table
模型进行搜索&amp; index使用view
模型。
例如
行动update
&amp; delete
使用Tag
模型
行动index
&amp; view
使用TagView
模型。