Question

当我尝试使用方法from scrapy.spider import BaseSpider from scrapy.selector import Selector from selenium import webdriver from selenium.webdriver.common.keys import Keys from scrapy.selector import HtmlXPathSelector import time import requests import csv class insiderSpider(BaseSpider): name = 'insider' allowed_domains = ["insider.in"] start_urls = ["http://www.insider.in/mumbai/"] def parse(self,response): driver = webdriver.Firefox() print response.url driver.get(response.url) s = Selector(response) #hxs = HtmlXPathSelector(response) source_link = [] temp = [] title ="" Price = "" Venue_name = "" Venue_address = "" description = "" event_details = [] alllinks = s.xpath('//div[@class="bottom-details-right"]//a/@href').extract() print alllinks length_of_alllinks = len(alllinks) for single_event in range(1,length_of_alllinks): if "https://insider.in/event" in alllinks[single_event]: source_link.append(alllinks[single_event]) driver.get(alllinks[single_event]) s = Selector(response) #hxs = HtmlXPathSelector(response) time.sleep(3) title = s.xpath('//div[@class = "cell-title in-headerTitle"]/h1//text()').extract() print title temp = s.xpath('//div[@class = "cell-caption centered in-header"]//h3//text()').extract() print temp time.sleep(2) a = len(s.xpath('//div[@class = "bold-caption price"]//text()').extract()) if a > 0: Price = s.xpath('//div[@class = "bold-caption price"]//text()').extract() time.sleep(2) else: Price = "RSVP" time.sleep(2) print Price Venue_name = s.xpath('//div[@class = "address"]//div[@class = "section-title"]//text()').extract() print Venue_name Venue_address = s.xpath('//div[@class ="address"]//div//text()[preceding-sibling::br]').extract() print Venue_address description = s.xpath('//div[@class="cell-caption accordion-padding"]//text()').extract() print description time.sleep(5) event_details.append([title,temp,Price,Venue_name,Venue_address,description]) else: print "Other part"发送消息时，我有一个来自SMSManager的错误。它返回[u'https://insider.in/weekender-music-festival-2015', u'https://insider.in/event/east-india-comedy-presents-back-benchers#', u'https://insider.in/event/art-of-story-telling', u'https://insider.in/feelings-in-india-with-kanan-gill', u'https://insider.in/event/the-tall-tales-workshop-capture-your-story', u'https://insider.in/halloween-by-the-pier-2015', u'https://insider.in/event/whats-your-story', u'https://insider.in/event/beyond-contemporary-art'] 2015-08-03 12:53:29 [selenium.webdriver.remote.remote_connection] DEBUG: POST http://127.0.0.1:60924/hub/session/f675b909-5515-41d4-a89e-d197c296023d/url {"url": "https://insider.in/event/east-india-comedy-presents-back-benchers#", "sessionId": "f675b909-5515-41d4-a89e-d197c296023d"} 2015-08-03 12:53:29 [selenium.webdriver.remote.remote_connection] DEBUG: Finished Request [] [] RSVP [] [] [] [[[], [], 'RSVP', [], [], []]]。

有我的代码：

sendTextMesasge

LogCat收到此消息：

java.lang.NullPointerException: Attempt to get length of null array

Answer 1

发现我的destNumber为空且不正确（不是电话号码）。这就是为什么我有一个java.lang.NullPointerException。

Answer 2

我已经在我的应用程序中发现了这几次（但从未在我的测试中），并试图找到解决方案数月。到目前为止，我找不到可以重现它的测试用例。

使用Sms.sendMultipartTextMessage方法：

SmsManager sms = SmsManager.getDefault();
ArrayList<String> parts = sms.divideMessage(msg);
sms.sendMultipartTextMessage(number, null, parts, null, null);

没有任何帮助 - 因为如果消息只有一个部分，它在内部最终会调用sendTextMessage - 但无论如何，如果你切换到它以防万一你有更长的消息可能是个好主意。

我最终将代码包装在try-catch中，并在服务器发生时向服务器报告。从我所看到的，看似“正常”的消息似乎触发了它。

有一个类似的情况here，但在这种情况下，邮件有一个PendingIntent for sent。你可能想尝试一下。

Answer 3

首先，您需要AndroidManifest.xml中的权限才能读取电话状态

<uses-permission android:name="android.permission.READ_PHONE_STATE"/>

然后尝试在Try Catch Block中获取移动设备数量。

getLine1Number（）可能会返回null值。所以你需要处理异常

try 
{
    myPhoneNumber = mTelephonyMgr.getLine1Number();
}
catch(NullPointerException ex)
{
}

Android：SMSManager - 尝试获取null数组的长度

3 个答案: