使用hibernate更新mysql表显示错误

时间:2015-08-03 05:04:48

标签: java mysql spring hibernate hql

在我的Spring项目中,我想根据url更新mysql表字段:

我的网址如下:

localhost:9191/access/name/article?key=xyz

我想从url中获取文章,然后更新相应的mysql表的状态和文章字段

在我的数据库中,我有表名“user”。

user(stu_id,name,email,article,status)

mysql查询是:

UPDATE user
SET article='null', status=true
WHERE article='xyz';  here xyz=user.getArticle()

为实现这一点,我已经完成了以下

User.java是:

public User(String article, String status) {
        super();
        this.article = article;
        this.status = status;
    }

UserDao.java

public interface UserDao {


     public void updateUser(User user);

}

UserDaoImpl.java是:

@Transactional
@Repository("userDao")
public class UserDaoImpl implements UserDao {
@Autowired
    private SessionFactory sessionFactory;

public void updateUser(User user) {


        String hql = "update user set article = null,status=true" 
                +"where article=:key1";

        sessionFactory.getCurrentSession().createQuery(hql)
        .setParameter("key1", user.getArticle());
        }
    }

UserService.java是:

public interface UserService {

    User updateUser(String article, String status);

}

UserServiceImpl.java是:

@Service("userService")
@Transactional(propagation = Propagation.SUPPORTS)
public class UserServiceImpl implements UserService {

public User updateUser(String article, String status) {


        User user = new User(article,status);


        userDao.updateUser(user);

        return user;

return user;
}

UserController.java是:

//localhost:9191/access/name/article?key=xyz 

@RequestMapping(value="/access/name/id", method=RequestMethod.GET)
public @ResponseBody String byParameter( User user, HttpServletRequest request) {

        boolean ps=true;
        String foo= request.getParameter("key");

        userService.updateUserinfo(foo, ps);


        return "signupLogin";
    }

但显示错误:

ERROR [] (ErrorCounter.java:56) - line 1:51: unexpected token: key
ERROR [] (ErrorCounter.java:56) - line 1:58: unexpected token: =

java.lang.IllegalArgumentException:要遍历的节点不能为空!

at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1760)
    at com.student.dao.UserDaoImpl.updateUser(UserDaoImpl.java:40)
    at com.student.service.UserServiceImpl.updateUserinfo(UserServiceImpl.java:66)

问题出在哪里?我做错了什么?

2 个答案:

答案 0 :(得分:1)

对sql查询进行以下更正,使用User代替user进行查询。

String hql = "update User set article = null, status = true where article = :key1";

如果您不想更改此方法,则可以使用createSqlQuery方法代替createQuery方法。

这个解决方案可能有所帮助。

答案 1 :(得分:1)

  at com.student.dao.UserDaoImpl.updateUser(UserDaoImpl.java:40)

您正在执行错误的查询。您应该执行以下代码:

@Transactional
@Repository("userDao")
public class UserDaoImpl implements UserDao {
@Autowired
    private SessionFactory sessionFactory;

public void updateUser(User user) {


        String hql = "update user set article = null,status=true" 
                +"where article=:key1";

        sessionFactory.getCurrentSession().createSQLQuery(hql)
        .setParameter("key1", user.getArticle());
        }
    }

语法如下: 其中用户(这是数据库表)和文章,状态是字段