Question

[{"code":10,"shtdesc":"CoOrdHR","name":"CO-ORDINATOR - HR","isselect":0}]

变化

(int to string)=> particular value "code"=10-> "code"="10" , "isselect":0->"isselect":"0"

我希望输出

[{"code":"10","shtdesc":"CoOrdHR","name":"CO-ORDINATOR - HR","isselect":"0"}]

Answer 1

尝试以下方法：

var data = [{"code":10,"shtdesc":"CoOrdHR","name":"CO-ORDINATOR - HR","isselect":0}];

data[0].code = String(data[0].code);

如果要将所有属性更改为字符串，则在数组的所有元素中，

function change_properties_to_strings(arr) {
  return arr.forEach(function(obj) {
    Object.keys(obj).forEach(function(key) {
      obj[key] = String(obj[key]);
    });
  });
}

换句话说，遍历数组的元素，每个元素都是一个对象。对于每个对象，循环其键（属性名称）。对于每个键，将该属性的值更改为字符串。

如果您更喜欢for-loops，可以使用相同的逻辑编写：

function change_properties_to_strings(arr) {
  for (var i = 0; i < arr.length; i++) {
    var obj = arr[i];
    for (var k in obj) {
      obj[k] = String(obj[k]);
    }
  }
}

Answer 2

在Java中：

我会删除所有打开和关闭括号/括号，然后按",|:"拆分。迭代数组，从分割中，如果它们不存在则在值周围添加引号，同时将它们添加回新构造的json String。

示例：

public static void main(String[] args) throws Exception {
    String json = "[{\"code\":10,\"shtdesc\":\"CoOrdHR\",\"name\":\"CO-ORDINATOR - HR\",\"isselect\":0}]";
    // Split out each value
    String[] jsonPieces = json.replaceAll("[\\[\\]{}]", "").split(",|:");

    // Reconstruct json
    StringBuilder sb = new StringBuilder("[{");
    for (int i = 0; i < jsonPieces.length; i++) {
        // Add quotes if they're not there
        if (!jsonPieces[i].startsWith("\"")) {
            jsonPieces[i] = "\"" + jsonPieces[i] + "\"";
        }
        // Append json piece
        sb.append(jsonPieces[i]);

        // Append ":" or "," 
        if (i + 1 < jsonPieces.length) {
            sb.append(i % 2 == 0 ? ":" : ",");
        } 
    }
    // Append closing
    sb.append("}]");

    // Reassign back to json
    json = sb.toString();

    // Display results
    System.out.println(json);
}

结果：

[{"code":"10","shtdesc":"CoOrdHR","name":"CO-ORDINATOR - HR","isselect":"0"}]

Answer 3

试试这个例子

＆＃13;

var arr = [{
  "code": 10,
  "shtdesc": "CoOrdHR",
  "name": "CO-ORDINATOR - HR",
  "isselect": 0
}];

alert(JSON.stringify(arr));

var transform = function(list) {
  var l = list.length;
  var o;
  while (l--) { //loop through each json
    o = list[l];
    for (var k in o) // loop through each key in json
      if ('number' === (typeof o[k])) // only if property value is number
        o[k] = o[k].toString();
  }
  return list;
};

alert(JSON.stringify(transform(arr)));

＆＃13;

我想要＆＃34;代码＆＃34; = 10变为＆＃34;代码＆＃34; =＆＃34; 10＆＃34;在JavaScript对象中

3 个答案: