Question

我正在使用Postie插件在我的Wp博客上自动发布电子邮件。我正在尝试使用“from”和“reply to”字段填充两个自定义字段（mail_meta_from和mail_meta_replyto“）

add_filter('postie_post_before', 'add_custom_field');

//Get the "from" and "replyto" email details

add_filter('postie_filter_email2', 'get_emaildetails', 10, 3);
function get_emaildetails( $from, $toEmail, $replytoEmail) {
  DebugEcho("step-01b");
  DebugDump("from " . $from);
  DebugDump("toEmail " . $toEmail);
  DebugDump("replytoEmail " . $replytoEmail);
  $fromField = $from;
  $replytoEmail = $replytoEmail;

  return $from;
  return $replytoEmail;
function add_custom_field($post) {
    add_post_meta($post['ID'], 'mail_meta_from', '$from');
    add_post_meta($post['ID'], 'mail_meta_replyto', $replytoEmail);
    return $post;
}
}

过去两天这让我疯了，我尝试了上述的多种变化但没有成功。目前，我收到了错误

Warning: call_user_func_array() expects parameter 1 to be a valid callback, function 'add_custom_field' not found or invalid function name in /home/sites/mysite.com/public_html/wp-includes/plugin.php on line 213

我试着从错误中吸取教训，但是我没有得到任何关于...... WP论坛的默认答案是查看http://postieplugin.com/extending/。

我有......反复。

非常感谢任何帮助！

Answer 1

您正在add_custom_field()函数范围内定义get_emaildetails()函数，因为它位于花括号内。您还应该考虑为函数使用更独特的名称，或者将其封装为对象名称空间。您收到的错误表示，当apply_filter()调用postie_post_before时，找不到名为add_custom_field()的函数。使用下面的代码来正确定位函数，但请注意您还有其他一些语法错误。

add_filter('postie_post_before', 'add_custom_field');
function add_custom_field($post) {
    // the variable $from is not defined, and it will not evaluate if enclosed 
    // in single quotes. if you want the value of $from define it then use "{$from}"
    add_post_meta($post['ID'], 'mail_meta_from', '$from');
    // $replytoEmail is not defined
    add_post_meta($post['ID'], 'mail_meta_replyto', $replytoEmail);
    return $post;
}

//Get the "from" and "replyto" email details
add_filter('postie_filter_email2', 'get_emaildetails', 10, 3);
function get_emaildetails( $from, $toEmail, $replytoEmail) {
  DebugEcho("step-01b");
  DebugDump("from " . $from);
  DebugDump("toEmail " . $toEmail);
  DebugDump("replytoEmail " . $replytoEmail);
  // what is this for?
  $fromField = $from;

  // setting to itself, then not used?
  $replytoEmail = $replytoEmail;

  return $from;

  // this will never return?
  return $replytoEmail;
}

从Wordpress Postie插件

1 个答案: