我想知道为什么以下代码中的getopt_long()不会为我的程序中当前定义的选项的无效选项或缺失值返回'?'或':'。此外，当我要打印optopt和opterr时，它不会反映我的计划的当前状态。
非常感谢你！
void parse_options(int argc,char **argv,program_options &opt)
{
int verbose_flag=0;
const char* opt_string =":k:s:c:g:o:t:f";
static struct option long_options[]=
{
{"verbose",no_argument,&verbose_flag,1},
{"filter",no_argument,NULL,'f'},
{"kmer size",required_argument,NULL,'k'},
{"gap size",required_argument,NULL,'s'},
{"coverage",required_argument,NULL,'c'},
{"threads",required_argument,NULL,'t'},
{"genome size",required_argument,NULL,'g'},
{"output file name",required_argument,NULL,'o'},
{NULL,no_argument,NULL,0}
};
int option_index=0;
int ch;
while((ch=getopt_long(argc,argv,opt_string,long_options,&option_index))!=-1)
{
/* if(ch==0)
{
std::cerr<<std::endl;
std::cerr<<"--- invalid option or missing value "<<std::endl;
print_usage();
exit(1);
}*/
if(ch=='k')
{opt.k=atoi(optarg);}
else if(ch=='s')
{opt.s=atoi(optarg);opt.compute_g=false;}
else if(ch=='c')
{opt.c=atoi(optarg);opt.compute_c=false;}
else if(ch=='t')
{opt.t=atoi(optarg);}
else if(ch=='g')
{opt.genomesize=atoll(optarg);}
else if(ch=='f')
{opt.filter = true;}
else if(ch=='o')
{opt.output_prefix_name=optarg;}
else if(ch=='?')
{std::cout<<" invalid option "<<std::endl;}
else if(ch==':')
{std::cout<<" option with missing argument"<<std::endl;}
}
for(int i=optind;i<argc;++i)
opt.read_files.push_back(argv[i]);
if(verbose_flag)
{opt.verbose=true;}
}