Question

我有一个实体Prototype与项目有多对一的关系，我想覆盖CRUDController中的一个函数。

以下是代码：

$idPrototype = $this->get('request')->get($this->admin->getIdParameter());

我得到原型的id，但我想要参数＆＃39; project＆＃39; （项目的ID）这是我的原型实体

    <?php

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Prototype
 *
 * @ORM\Table()
 * @ORM\Entity(repositoryClass="AppBundle\Entity\PrototypeRepository")
 */
class Prototype
{
/**
 * @var integer
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $id;

/**
 * @var string
 *
 * @ORM\Column(name="nom", type="string", length=255)
 */
private $nom;


/**
 * @var string
 *
 * @ORM\Column(name="description", type="string", length=255)
 */
private $description;

/**
 * @var \DateTime
 *
 * @ORM\Column(name="dateCreation", type="date")
 */
private $dateCreation;

private $projet;


public function __construct()
{   
    $this->dateCreation =  new \DateTime("now");
    $this->nom = "";
    $this->description = " ";
}


/**
 * Get id
 *
 * @return integer 
 */
public function getId()
{
    return $this->id;
}


/**
 * Get nom
 *
 * @return string 
 */
public function getNom()
{
    return $this->nom;
}

public function __toString()
{
return $this->getNom();
}

/**
 * Set nom
 *
 * @param string $nom
 * @return Prototype
 */
public function setNom($nom)
{
    $this->nom = $nom;

    return $this;
}


/**
 * Set description
 *
 * @param string $description
 * @return Prototype
 */
public function setDescription($description)
{
    $this->description = $description;

    return $this;
}

/**
 * Get description
 *
 * @return string 
 */
public function getDescription()
{
    return $this->description;
}

/**
 * Set dateCreation
 *
 * @param \DateTime $dateCreation
 * @return Prototype
 */
public function setDateCreation($dateCreation)
{
    $this->dateCreation = $dateCreation;

    return $this;
}

/**
 * Get dateCreation
 *
 * @return \DateTime 
 */
public function getDateCreation()
{
    return $this->dateCreation;
}


/**
 * Set projet
 *
 * @param \AppBundle\Entity\Projet $projet
 * @return Prototype
 */
public function setProjet(\AppBundle\Entity\Projet $projet = null)
{
    $this->projet = $projet;
    return $this;
}

/**
 * Get projet
 *
 * @return \AppBundle\Entity\Projet 
 */
public function getProjet()
{
    return $this->projet;
}

}

我试过使用ModelManager（）但是我得到了这个错误＆＃34;试图调用名为＆＃34; getModelManager＆＃34;的未定义方法。 class＆＃34; AppBundle \ Controller \ CRUDProtoController＆＃34;。＆＃34; 我是奏鸣曲和symfony的新人，我发现它有困难。

Sonata AdminBundle，获取实体

0 个答案: