我试图找到一种在数组元素之间添加新行的方法。我有一个超过JSON数据的php文件,因为我有这一行 - <p>
由于这些数据总是打印在一行,<br>
,\n
,$vs['title']
是被视为文本而不是代码。 while只是从查询中运行数据,该查询将值插入$vs['description']
和Title - my title
Value - my value
。
如何让它像这样打印:
Title - my title Value - my value
而不是:
$vs1=array();
while($res2 = oci_fetch_array($result2)) {
$vs=array();
$vs['title']='Title'.$res2['CATEGORIA_DESC'];
$vs['description']= 'Value - '.$res2['VALOR'];
array_push($vs1,$vs);
}
echo str_replace(array('[', ']'), '', htmlspecialchars(json_encode($vs1), ENT_NOQUOTES));
PHP文件的一部分
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>
#include <stdlib.h>
#include <signal.h>
#include <stdbool.h>
#include <string.h>
#include "tpl.h"
//This example contains two different parts:
//1) The alarm is a execution timer for the function doWork
//2) There is a need, that if the execution exits correctly, that the chid value of i, that we are modifying be passes
typedef struct TEST_STRUCT
{
int i;
double sum;
} testStruct;
int doWork(testStruct * ts)
{
int y;
for(y=0; y<3; y++)
{
sleep(1);
printf("Working: %d\n", ts->i);
ts->i++;
ts->sum += (double)ts->i;
}
return 0;
}
int main()
{
testStruct * ts = (testStruct *)(calloc(1, sizeof(testStruct)));
ts->i = 7;
ts->sum = 4.0;
tpl_node *tn;
int fd[2];
pipe(fd);
int y;
for(y=0; y<10; y++)
{
pid_t childPID = fork();
if (childPID==0)
{
unsigned secsLeft;
alarm(10);
doWork(ts);
printf("\t->%d\n", ts->i);
printf("\t->%p\n", (void*) &ts->i);
tn = tpl_map("S(if)", ts);
tpl_pack( tn, 0 );
tpl_dump( tn, TPL_FD, fd[1]);
tpl_free( tn );
secsLeft = alarm(0);
exit(0);
}
else
{
//IMPORTANT TO PUT IT HERE: In case the buffer is too big, TPL_DUMP will wait until it can send another and hang
tn = tpl_map( "S(if)", ts );
tpl_load( tn, TPL_FD, fd[0]);
int status;
wait(&status);
if(WIFSIGNALED(status))
{
// child was interrupted
if (WTERMSIG(status) == SIGALRM)
{
printf("Interrupted\n");
// child interrupted by alarm signal
}
else
{
printf("Should not happend\n");
// child interrupted by another signal
}
}
else
{
tpl_unpack(tn,0);
tpl_free( tn );
printf("\t->%d\n", ts->i);
printf("\t->%p\n", (void*) &ts->i);
printf("Success\n");
}
}
}
return 0;
}
答案 0 :(得分:0)
如果您只想显示数据,可以在while循环中执行:
while ($res2 = oci_fetch_array($result2)) {
echo "<hr/>";
echo "<div>Title {$res2['CATEGORIA_DESC']}</div>";
echo "<div>Value - {$res2['VALOR']}</div>";
}