哪个“.h”文件用于越狱调整

时间:2015-08-02 09:49:20

标签: ios jailbreak

所以我对 Objective C 很新,只是想做一个调整!代码在 Xcode 上运行良好,但我想改变它以便它可以作为越狱调整。基本上当你在家里屏幕/跳板时,你只需点击并按住屏幕一秒钟,然后给你一个带有3个按钮的UIAlertView。我只是想知道如何在跳板上翻译它!我应该使用哪个头文件!

这是我在 Xcode 上使用的代码:

- (void)viewDidLoad
{
    [super viewDidLoad];

self.lpgr = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPressGestures:)];
self.lpgr.minimumPressDuration = 1.0f;
self.lpgr.allowableMovement = 100.0f;

[self.view addGestureRecognizer:self.lpgr];
}

- (void)handleLongPressGestures:(UILongPressGestureRecognizer *)sender
  {
     if ([sender isEqual:self.lpgr]) 
   {
    if (sender.state == UIGestureRecognizerStateBegan)
    {
          UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Gestures" message:@"Long Gesture Detected" delegate:self cancelButtonTitle:@"Cancel" otherButtonTitles:@"Message", @"Facetime", @"Phone", nil];
        [alertView show];

    }
}
}


  - (void)alertView:(UIAlertView *)alertView didDismissWithButtonIndex:(NSInteger)buttonIndex
 {
if (buttonIndex == 1)
{
    NSLog(@"Message");
   [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"sms:+1234567890"]];


}

if (buttonIndex == 2)
{
    NSLog(@"Facetime");
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"facetime://tel-number"]];


}
if (buttonIndex == 3)
{
    NSLog(@"Phone");
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:%@"]];

}

   }

0 个答案:

没有答案