Question

我的每个单元格都有一个弹出框，如下例所示：

对popover的调用：

<td ng-repeat="i in c.installments" ng-class="{ 'first' : i.first, 'last' : i.last, 'advance' : i.advance.value > 0, 'edited' : i.edited, 'final-installment' : i.last }" popover-trigger="{{ popoverFilter(i) }}" popover-placement="top" popover-title="{{i.id == 0 ? 'Advance' : 'Installment ' + i.id}}" popover-append-to-body="true" popover-template="popoverTemplate(i)" ng-init="payment= i; newpayment= i.amount.rounded_value" >

弹出模板：

<script type="text/ng-template" id="editPopoverTemplate.html">
    <form name="editPayment">
      <h2>{{payment.amount.value|currency:undefined:cents}}</h2>
      <div class="form-group" ng-class="{ 'has-error' : editPayment.newpayment.$invalid }">
        <label>New value:</label>
        <input type="number" name="newpayment" ng-model="newpayment" class="form-control no-spinner" step="1" min="10" required>
        <span ng-messages="editPayment.newpayment.$error" class="help-block" role="alert">
          <span ng-message="required">The value is mandatory</span>
          <span ng-message="min">The value is too low</span>
          <span ng-message="max">The value is too hight</span>
        </span>
      </div>
      <div class="btn-group btn-group-justified" role="group">
        <div class="btn-group" role="group">
          <button class="btn" type="button">Cancel</button>
        </div>
        <div class="btn-group" role="group">
          <button class="btn btn-primary" type="button" ng-disabled="editPayment.$invalid">Save</button>
        </div>
      </div>
    </form>
  </script>

working example on plunker

我需要通过＆＃34;取消＆＃34;关闭popover。弹出窗口内的按钮。可能吗？我需要扩展Angular UI Bootstrap库吗？

感谢任何帮助。

链接答案中建议的解决方案在用户点击弹出窗口内部或弹出窗口外时关闭弹出窗口，但我需要通过＆＃34;关闭＆＃34;弹出窗口内的按钮。

Answer 1

使用新的popover-is-open属性的正确解决方案，如下面的@icfantv所述，允许使用控制器范围。我在Codepen中放了一个实例，它是这样的：

app = angular.module('ui.bootstrap.demo', ['ui.bootstrap']);

app.controller(
  'myPopoverCtrl', ['$scope',
    function($scope) {

      // query popover
      $scope.myPopover = {

        isOpen: false,

        templateUrl: 'myPopoverTemplate.html',

        open: function open() {
          $scope.myPopover.isOpen = true;
          $scope.myPopover.data = 'Hello!';
        },

        close: function close() {
          $scope.myPopover.isOpen = false;
        }
      };

    }

  ]);

<head>

  <script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
  <script src="//ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
  <script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
  <script src="//cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/0.13.4/ui-bootstrap-tpls.min.js">
  </script>
  <link rel="stylesheet" href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">

</head>

<body 
      ng-app="ui.bootstrap.demo" 
      class="container">

  <button 
          class="btn btn-danger" 
          ng-controller="myPopoverCtrl" 
          popover-template="myPopover.templateUrl" 
          popover-title="This is a popover" 
          popover-placement="bottom" 
          popover-is-open="myPopover.isOpen" 
          ng-click="myPopover.open()">Click me!</button>

  <script type="text/ng-template" 
          id="myPopoverTemplate.html">
    <h2 ng-bind="myPopover.data" />
    <button class="btn btn-success" 
            ng-click="myPopover.close()">Close me!</button>

  </script>

</body>

原始回答：

我花了最后两天来解决这个问题，最后提出了一个简单的黑客攻击。这发生在我的控制器上：

 $scope.close = function(e) {
     el = angular.element(e.target).closest("td"); // `td` is the parent of my clickable
                                                   // element, in this case a `span`
     $timeout(function() { // need $timeout so we don't conflict with the digest loop
     el.children(":first").trigger('close'); // couldn't select the `span` element directly
     });
 },

现在我们在提供商处设置关闭触发器：

app.config(['$tooltipProvider', function($tooltipProvider){
  $tooltipProvider.setTriggers({
    'click': 'close', // Clicks now only open the tooltip, 'close' events close it.
  });
}]);

在我的自定义popover HTML模板上：

<button type="button" 
        class="btn btn-sm btn-success pull-right" 
        ng-click="close($event)">Close</button>

瞧！我现在可以通过按钮关闭弹出窗口了！

Answer 2

此解决方案适用于通过ng-repeat范围内的isOpen字段进行的多个angular.module('ui.bootstrap.demo', ['ui.bootstrap']).controller('PopoverDemoCtrl', function ($scope) { $scope.template = 'myPopoverTemplate.html'; $scope.close = function(e) { angular.element(e.target).parent().parent().parent().parent().scope().$parent.isOpen = false; } });弹出广告。

＆＃13;

<script src="//ajax.googleapis.com/ajax/libs/angularjs/1.6.1/angular.js"></script>
<script src="//angular-ui.github.io/bootstrap/ui-bootstrap-tpls-2.5.0.js"></script>
<link href="//netdna.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet">

<body ng-app="ui.bootstrap.demo">
<div ng-controller="PopoverDemoCtrl">
    <button ng-repeat="item in ['First Popover','Second Popover','Third Popover']" popover-placement='bottom' uib-popover-template="template" popover-title="{{item}}" type="button" class="btn btn-default">{{item}}</button>  
    <script type="text/ng-template" id="myPopoverTemplate.html">        
        <div class="form-group">
          <button class='btn btn-danger' ng-click='close($event)'>Close Me</button>
        </div>
    </script>
</div>
</body>

＆＃13;

Reviewer

＆＃13;

Answer 3

从Angular UI Bootstrap版本0.13.4开始，我们添加了通过tooltip-is-open或popover-is-open布尔属性以编程方式关闭工具提示和弹出窗口的功能。

Angular UI Bootstrap Popover - 如何添加关闭按钮

3 个答案: