Question

我在为我的代码执行正确的语法时遇到了一些麻烦。我总结一下员工在特定周工作的小时数，但我想从查询中排除某些天数。员工可以为不同的客户工作，这些客户由client_id定义。

现在下面的代码在parantheses内的WHERE语句中有一个语法错误，我知道为什么，我只是让他们在那里为了解释我想在这种情况下实现的目标。

我感谢你能给我的任何帮助。

顺便说一句：我也尝试了AND（DAYOFWEEK（日期）＆lt;＆gt; 7 AND client_id ='1'）但这也不起作用。我重新判断这是因为我的查询只返回一行结果，因此我的上述代码在查询循环时不执行任何操作

SELECT
    date,
    client_id,
    SUM(hours)-37.5 AS total,
    SUM(lunch = 'yes') AS lunch
FROM
    hours
WHERE
    CONCAT(WEEK(date, 1)) = '25'
AND
    CONCAT(YEAR(date)) = '2015'
AND
    employee_id = '14'
AND ( DAYOFWEEK(date) <> 7 WHERE client_id = '1' )  
AND ( DAYOFWEEK(date) <> 1 WHERE client_id = '2' ) 
AND
    status = 'billed'
HAVING SUM(hours) > 37.5

Answer 1

您可以使用一堆逻辑not和and逻辑运算符来构建此逻辑：

SELECT
    date,
    client_id,
    SUM(hours)-37.5 AS total,
    SUM(lunch = 'yes') AS lunch
FROM
    hours
WHERE
    CONCAT(WEEK(date, 1)) = '25'
AND
    CONCAT(YEAR(date)) = '2015'
AND
    employee_id = '14'
AND NOT ( DAYOFWEEK(date) = 7 AND client_id = '1' )  
AND NOT ( DAYOFWEEK(date) = 1 AND client_id = '2' ) 
AND
    status = 'billed'
HAVING SUM(hours) > 37.5

Mysql排除星期六，其他值等于

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