PyQt QMessageBox粉碎程序

Question

我的代码有问题。如何更正下面的代码到QMessageBox不崩溃程序？我不知道为什么这个问题确实存在。我尝试在新的QThread中运行QMessageBox，但它什么都没改变。

import sys
from time import sleep
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *
from PyQt5.QtGui import *

class Signals(QObject):
    update = pyqtSignal(int)
    enable_button = pyqtSignal(bool)

class Window(QWidget):
    def __init__(self, *args, **kwargs):
        QWidget.__init__(self, *args, **kwargs)

        self.button = QPushButton("Run", self)
        self.button.clicked.connect(self.onButton)

        self.progress = QProgressBar(self)
        self.progress.setTextVisible(False)

        self.layout = QVBoxLayout()
        self.layout.setContentsMargins(5, 5, 5, 5)
        self.layout.addWidget(self.button)
        self.layout.addWidget(self.progress)
        self.layout.addStretch()

        self.worker_thread = QThread()
        self.worker_thread.run =  self.worker
        self.worker_thread.should_close = False

        self.signals = Signals()
        self.signals.update.connect(self.progress.setValue)
        self.signals.enable_button.connect(self.button.setEnabled)

        self.setLayout(self.layout)
        self.show()
        self.resize(self.size().width(), 0)

    def closeEvent(self, e):
        self.worker_thread.should_close = True
        self.worker_thread.wait()

    @pyqtSlot()
    def onButton(self):
        self.button.setDisabled(True)
        self.worker_thread.start()

    def worker(self):
        for i in range(101):
            if self.worker_thread.should_close:
                break
            self.signals.update.emit(i)
            sleep(0.1)
        msgBox = QMessageBox(QMessageBox.Information, "Ok", "Done.", QMessageBox.NoButton)
        icon = QIcon()
        icon.addPixmap(QPixmap(":/favicon.ico"), QIcon.Normal, QIcon.Off)
        msgBox.setWindowIcon(icon)
        msgBox.addButton("Ok", QMessageBox.AcceptRole)
        msgBox.exec_()
        self.signals.enable_button.emit(True)

app = QApplication(sys.argv)
win = Window()
sys.exit(app.exec_())