#include<stdio.h>
int partition(int p[],int lb,int ub)
{
int i,temp,up,down,pivot;
pivot=p[lb];
up=ub;
down=lb;
while(down<up)
{
while(p[down]<=pivot&&down<ub)
down++;
while(p[up]>pivot)
up--;
if(down<up) //exchange them
{
temp=p[down];
p[down]=p[up];
p[up]=temp;
}
}
temp=p[lb];
p[lb]=p[up];
p[up]=temp;
return up;
}
void myqsort(int a[], int lb,int ub)
{
int q=partition(a,lb,ub);
myqsort(a,lb,q-1);
myqsort(a,q+1,ub);
}
int main()
{
int m[]={1,2,5,6,3};
for(int i=0;i<5;i++)
printf("%d",m[i]);
myqsort(m,0,4);
for(int i=0;i<5;i++)
printf("%d",m[i]);
return 0;
}
上面的代码给出了分段错误。 它是一个递归的快速排序我在c中实现。 看看其他答案,但他们没有解决我的情况。 知道出了什么问题吗? 知道我做错了什么吗?
答案 0 :(得分:4)
当我gdb
编写代码时,堆栈跟踪结果很糟糕。
#0 partition (p=0xbffff8a4, lb=0, ub=-174722) at qs.c:3
#1 0x08048525 in myqsort (a=0xbffff8a4, lb=0, ub=-174722) at qs.c:33
#2 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174721) at qs.c:34
#3 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174720) at qs.c:34
#4 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174719) at qs.c:34
#5 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174718) at qs.c:34
#6 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174717) at qs.c:34
#7 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174716) at qs.c:34
#8 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174715) at qs.c:34
#9 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174714) at qs.c:34
#10 0x08048540 in myqsort (a=0xbffff8a4, lb=0, ub=-174713) at qs.c:34
....
函数myqsort
无限递归。
您应该在myqsort
void myqsort(int a[], int lb,int ub)
{
if (lb >= ub)
return;
int q=partition(a,lb,ub);
myqsort(a,lb,q-1);
myqsort(a,q+1,ub);
}