Question

我将这个json保存在我的数据库中名为'price'的列中，其类型为'text'。

{
  "desks": {
    "Dedicated Desk": "$400 mo"
  },
  "private offices": {
    "1 Person": "$550 mo",
    "2 Person": "$1100 mo",
    "3 Person": "$1600 mo",
    "4 Person": "$2100 mo",
    "6 Person": "$3300 mo"
  },
  "flexible membership": {
    "Starting at": "$45 mo",
    "Every Extra Day": "$50 Day"
  }
}

然后我从PHP调用返回我数据库中的所有字段并将它们编码为json。

$json = json_encode($response,JSON_PRETTY_PRINT);
echo $json;

$ response是数据库的响应。当我对$ response进行var_dump时，我得到了

array(22) {
    [0]=>
      object(stdClass)#6 (38) {
        [...]

        ["price"]=>
        string(242) "{"desks":{"Dedicated Desk":"$400 mo"},"private offices":{"1 Person":"$550 mo","2 Person":"$1100 mo","3 Person":"$1600 mo","4 Person":"$2100 mo","6 Person":"$3300 mo"},"flexible membership":{"Starting at":"$45 mo","Every Extra Day":"$50 Day"}}"

        [...]
      }
    [...]
}

当我从json_encode回显结果时，我得到了

[
    {
        [...]

        "price": "{\"desks\":{\"Dedicated Desk\":\"$400 mo\"},\"private offices\":{\"1 Person\":\"$550 mo\",\"2 Person\":\"$1100 mo\",\"3 Person\":\"$1600 mo\",\"4 Person\":\"$2100 mo\",\"6 Person\":\"$3300 mo\"},\"flexible membership\":{\"Starting at\":\"$45 mo\",\"Every Extra Day\":\"$50 Day\"}}",

        [...]
    },
    [...]
]

我的问题是json_encode从数据库中获取json并将其格式化为字符串。我试图让它将其格式化为多维json结构的一部分。这就是我想要实现的目标：

[  
   {  
      "price":[  
         {  
            "desks":{  
               "Dedicated Desk":"$400 mo"
            },
            "private offices":{  
               "1 Person":"$550 mo",
               "2 Person":"$1100 mo",
               "3 Person":"$1600 mo",
               "4 Person":"$2100 mo",
               "6 Person":"$3300 mo"
            },
            "flexible membership":{  
               "Starting at":"$45 mo",
               "Every Extra Day":"$50 Day"
            }
         }
      ]
   }
]

任何帮助将不胜感激。运行最新版本的php。

Answer 1

它将其编码为字符串，因为它是一个字符串。你需要做的是先解码它。

 $response['price'] = json_decode($response['price']);
 $json = json_encode($response,JSON_PRETTY_PRINT);
 echo $json;

json_decode来自数据库

1 个答案: