Question

我想创建一个在每个字符之间延迟的操纵器，就像我写的那样

delay wait = 40;
cout << wait << "Hello World!";

它应该输出'H'然后睡眠（40），'e'然后睡眠（40），'l'然后睡眠（40）等等，我试着为此写一个类，这是我的代码：

class delay {

public:
    delay(const int& amount) {                        // getting the amount for Sleep(...)
        this->Amount = amount;
    }
    delay& delay::operator = (const int& amount) {    // same, but for operator=
        this->Amount = amount
        return *this;
    }

private:
    ostream& m_os;
    int Amount;
    friend ostream& operator << (ostream& os, delay& p) {    // i dont know if I even need this
        p.m_os = os;
        return os;
    }
    friend ostream& operator << (delay& p, const char* n) {  // here it should do output and delay
        int index = 0;
        while (n[index] != '\0) {
            p.m_os << n[index];    // output character
            index++;
            Sleep(p.Amount);       // wait
        }
    return p.m_os;
    }

};

当我尝试使用此代码时出现错误，我觉得我必须从头开始重写。我希望你知道如何实现这个延迟课，因为我尽我所能，但它不起作用。感谢您阅读本文，我希望您能帮助我<3

Answer 1

cout << wait << "Hello World!"; is (cout << wait) << "Hello World!"; so your operator never gets invoked. Simple debugging would have shown this! You will need a proxy object, basically. Still, I don't think you should do this. You'll block the thread. Why not use a proper task scheduler to produce output on a schedule?

如何在使用cout时创建一个操作文本的类？

1 个答案: