Question

我正在使用代码优先方法使用Entity Framework。我已经成功地为多对多关系（类型到状态）播种数据。现在我需要为Status和SubStatus之间的多对多关系建立数据。

我首先创建所有状态，然后添加每个类型并添加每个状态的多对多关系。

以下是我的类型和状态：

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我如何构建它，然后立即添加Status和SubStatus之间的多对多关系？

这里列出了几个SubStatuses：

    IList<Status> statuses = new List<Status>();

    statuses .Add(new Status() { Value = "On" });
    statuses .Add(new Status() { Value = "Off" });

    foreach (Status s in statuses)
    {
        context.Set<Status>().AddOrUpdate(s);
    }

    Type type1 = new Type()
    {
        Value = "Type 1",
        Status = new List<Status>()  
        {
            statuses.FirstOrDefault(e => e.Value == "On"),
            statuses.FirstOrDefault(e => e.Value == "Off")
        }
    };
    Type type2 = new Type() 
    { 
        Value = "Type 2", 
        Status = new List<Status>()  
        {
            statuses.FirstOrDefault(e => e.Value == "On"),
        }
    };

Answer 1

我相信您正在寻找父母/子女的关系？您可以像这样重新构建Status实体并删除SubSatus类：

public class Type
{
     public string Value {get;set;}
     public ICollection<Status> Statuses {get;set;}
{

public class Status
{
      public string Value {get;set;}
      public int? ParentStatusId {get;set;}
      public Status ParentStatus {get;set;}
      public ICollection<Status> ChildStatuses {get;set;}
      Public ICollection<Type> Types {get;set;}

}

然后，您可以附加ChildStatuses并将其与ParentStatus

相关联

var typeA = new Type()
            {
               Value = "Type A"
            };

var typeB = new Type()
            {
               Value = "Type B"
            };
var statuses = new List<Status>(){
                     new Status()
                     {
                         Value = "On",
                         ChildStatuses = new List<Status>(){
                                               new Status()
                                               {
                                                  Value = "Success",
                                                  Types = new List<Type>()
                                                          {
                                                            typeA,
                                                            typeB
                                                          }
                                               },
                                               new Status()
                                               {
                                                  Value = "Fail",
                                                  Types = new List<Type>()
                                                          {
                                                            typeB

                                                          }
                                               }
                     }
                   };


context.Set<Status>().AddOrUpdate(s => s.Value, statuses.ToArray() );

种子代码首先是多对多的多对多

1 个答案: