Question

我在包含以下数据的网址中有一个json Feed。

<string xmlns="http://schemas.microsoft.com/2003/10/Serialization/">
[{"ID":1123,"OrderNumber":"1394","ProjectType":"Postcard","Template":"WtlossStudy solo","TemplateURL":"someone.biz/Home/ShowTemplate/283","ShipDate":"2/28/2015","InHomeDate":"3/2/2015","Quantity":"10,000","Price":"$3,000","CallTracking":"0"},{"ID":1123,"OrderNumber":"1413","ProjectType":"Postcard","Template":"WtlossStudy solo","TemplateURL":"","ShipDate":"3/30/2015","InHomeDate":"3/31/2015","Quantity":"5,000","Price":"$1,500","CallTracking":"0"},{"ID":1123,"OrderNumber":"1413","ProjectType":"Postcard","Template":"WtlossStudy solo","TemplateURL":"","ShipDate":"4/13/2015","InHomeDate":"4/14/2015","Quantity":"5,000","Price":"$1,500","CallTracking":"0"}]
</string>

我需要得到它并通过php解析它。但它使用以下代码给出了无效的foreach错误。任何人都可以帮我解决如何正确显示。

$json = file_get_contents('http://someurl.biz/api/api/1123');

$obj = json_decode($json, true);

foreach($obj as $ob) {
    echo $ob->ID;
}

Answer 1

尝试

$json = file_get_contents('http://superiorpostcards.biz/api/api/1123');
$obj = json_decode($json, true);
$array = json_decode($obj, true);
foreach($array as $value){
    echo $value['ID'];
}

Answer 2

这很有效。

当你的JSON成为一个关联数组时，你必须做出2个foreach。

Top foreach解析3＆＃34;对象＆＃34;在＆＃39; [object1，object2，object3]＆＃39;

底部的foreach解析每个＆＃34;对象＆＃34;含量

$data = json_decode('[{"ID":1123,"OrderNumber":"1394","ProjectType":"Postcard","Template":"WtlossStudy solo","TemplateURL":"someone.biz/Home/ShowTemplate/283","ShipDate":"2/28/2015","InHomeDate":"3/2/2015","Quantity":"10,000","Price":"$3,000","CallTracking":"0"},{"ID":1123,"OrderNumber":"1413","ProjectType":"Postcard","Template":"WtlossStudy solo","TemplateURL":"","ShipDate":"3/30/2015","InHomeDate":"3/31/2015","Quantity":"5,000","Price":"$1,500","CallTracking":"0"},{"ID":1123,"OrderNumber":"1413","ProjectType":"Postcard","Template":"WtlossStudy solo","TemplateURL":"","ShipDate":"4/13/2015","InHomeDate":"4/14/2015","Quantity":"5,000","Price":"$1,500","CallTracking":"0"}]');

 foreach($data as $obj) {
     foreach($obj as $key=>$val) {
        echo $key."->".$val." | ";
     }
 }

是的，JS更简单。但是php＆＃34; json＆＃34;不是JS对象，它是一个关联数组的数组。

Answer 3

$my_array_for_parsing = json_decode(/** put the json here */);

这使得JSon成为php associative 数组。

$my_array_for_parsing = json_decode($json);
foreach ($my_array_for_parsing as $name => $value) {
    // This will loop three times:
    //     $name = a
    //     $name = b
    //     $name = c
    // ...with $value as the value of that property
}

Answer 4

如果json_decode的第二个参数设置为true，则json将在关联数组中而不是对象中进行转换。试试这个：

$obj = json_decode($json, false);

foreach($obj as $ob) {
    echo $ob->ID;
}

解析JSON Feed

4 个答案: