Question

嗨我从post使用serialize函数得到的值显示错误的值。它只显示N ..请帮助我

Php Code

$item_select_alpha = $_POST['item_select_alpha'];
for ($alpha = 1; $alpha <= count($item_select_alpha); $alpha++) {
    $serialise = serialize(array($item_select_alpha[$alpha]));
}
$item_quanity = $_POST['item_quanity'];
for ($qty = 1; $qty <= sizeof($item_quanity); $qty++) {
    $item_quan = serialize($item_quanity[$qty]);
}
print_r($item_quan);
exit;

HTML代码

<select class="item_select_alpha" name="item_select_alpha[]">
    <option value="">select the Alphabetic</option>
    {foreach $size_alpha as $sa}
    <option value="{$sa['size_id']}">{$sa['size_name']}</option>
    {/foreach}
</select>

<input type="text" class="item_quanity" name="item_quanity[]" class="form-control">

Answer 1

for循环中的变量将只包含最后一个元素，在每次迭代时更新它们的值。在第二个循环中定义的$ item_quan不会是＆＃34;可打印＆＃34;离开了...

Answer 2

您不能向数组添加项目，只会更改变量，使其包含最后一个元素。试试这个：

    $serialise[] = serialize(array($item_select_alpha[$alpha]));

    $item_quan[] = serialize($item_quanity[$qty]);

序列化功能在php中不起作用

2 个答案: