Question

我正在做这样的动态调整，我想在旋转后用0替换字段中的Null值。不知道我怎么能实现这一点。这是我的询问。

DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
DECLARE @users TABLE (
	userId UNIQUEIDENTIFIER
	,NAME VARCHAR(500)
	);


INSERT INTO @users
SELECT u.id
	,u.firstname + space(1) + u.lastname NAME
FROM users u
INNER JOIN userparametervalues upv ON u.id = upv.userid
INNER JOIN UserPermissions up ON u.id = up.userid
	AND up.PermissionId IN (
		'34FDF821-E3FF-43B2-AA90-0126BF5FAD56'
		,'CFC3076F-0BED-4A41-BD1D-0240C4535132'
		)
	AND upv.parameterid = '137696EA-6B68-42E8-A020-2FA5A833F34E'
INNER JOIN users AS u1 ON upv.value = u1.id
	AND u1.UserName IN (
		'IN\libin.jose'
		,'IN\Pallabi.P'
		)

UNION

SELECT users.id id
	,users.firstname + space(1) + users.lastname NAME
FROM users
WHERE UserName IN (
		'IN\libin.jose'
		,'IN\Pallabi.P'
		)


SELECT @cols = STUFF((
			SELECT DISTINCT ',' + QUOTENAME(NAME)
			FROM @users
			FOR XML PATH('')
				,TYPE
			).value('.', 'NVARCHAR(MAX)'), 1, 1, '');
SELECT @query = '

SELECT *
FROM
(
  select  LoanPrograms.Name, (case when UserParameterValues.value is null then ''X'' else ''√'' end) as K ,(users.FirstName + space(1)+users.LastName  ) L from LoanPrograms 
	left join UserParameterValues on LoanPrograms.id = UserParameterValues.ValueId and ParameterId = ''CD1DB446-75EF-4887-86ED-4313CCE6D2F1''
		left join users on UserParameterValues.UserId = Users.Id	

) AS t
PIVOT 
(
MAX(k)
  FOR L IN( ' + @cols + ' )' + ' ) AS p ; ';

EXECUTE (@query);

我得到的结果就是这些。

Name	                                Akansha a	Lia Jose	Libin 	Pallabi a
-----------------                       ---------- ---------   -------- ------
CONF 10 YEAR FIXED	                   NULL     	NULL	    NULL	Y
CONF 10 YR 105                        	 NULL	    NULL	    NULL	NULL
CONF 10 YR 125 	                         NULL	    Y	        NULL	NULL
CONF 10 YR LPMI	                         Y   	    NULL	    NULL	NULL
CONF 10/1 LIBOR ARM                  	 NULL	    NULL	    NULL	NULL

我想将所有空值替换为0。

Answer 1

您需要在ISNULL的最终SELECT中使用PIVOT功能。例如，您可以像这样构建列列表：

SELECT @SELECTEDcols = STUFF((
            SELECT DISTINCT ',ISNULL([' + NAME + '], 0) AS [' + NAME + ']'
            FROM @users
            FOR XML PATH('')
                ,TYPE
            ).value('.', 'NVARCHAR(MAX)'), 1, 1, '');

并用最终*语句替换SELECT。

SELECT @query = '

SELECT' + @SELECTEDcols + ' 
FROM
(
  select  LoanPrograms.Name, (case when UserParameterValues.value is null then ''X'' else ''√'' end) as K ,(users.FirstName + space(1)+users.LastName  ) L from LoanPrograms 
    left join UserParameterValues on LoanPrograms.id = UserParameterValues.ValueId and ParameterId = ''CD1DB446-75EF-4887-86ED-4313CCE6D2F1''
        left join users on UserParameterValues.UserId = Users.Id    

) AS t
PIVOT 
(
MAX(k)
  FOR L IN( ' + @cols + ' )' + ' ) AS p ; ';

Answer 2

SELECT @SELECTEDcols = STUFF((
            SELECT DISTINCT ',ISNULL([' + NAME + '], 0) AS [' +NAME + ']'
            FROM @users
            FOR XML PATH('')
                ,TYPE
            ).value('.', 'NVARCHAR(MAX)'), 1, 1, '');


SELECT @query = '

SELECT' + @SELECTEDcols + ' 
FROM
(
  select  LoanPrograms.Name, (case when UserParameterValues.value is null then ''X'' else ''√'' end) as K ,(users.FirstName + space(1)+users.LastName  ) L from LoanPrograms 
    left join UserParameterValues on LoanPrograms.id = UserParameterValues.ValueId and ParameterId = ''CD1DB446-75EF-4887-86ED-4313CCE6D2F1''
        left join users on UserParameterValues.UserId = Users.Id    

) AS t
PIVOT 
(
MAX(k)
  FOR L IN( ' + @cols + ' )' + ' ) AS p ; ';

处理动态数据透视表字段中的空值

2 个答案: