Question

下面我发布了嵌套的JSON响应。我希望将所有键和键值加载到一个tableview中，如下面的UI。请帮帮我！

我的JSON

response : {

     ANI =  { 
             name = "anisharmu";
             age  = "10";
     };

     ROC =  { 
             name = "rockins";
             age  = "20";   
     };
}

MY UI Tableview

|------------------------|
  ANI anisharmu - 10
|------------------------|

我的代码

 NSError *error;
 jsonDictionary = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
 // get keys from response dictionary
 NSMutableArray * key = [[NSMutableArray alloc] initWithArray:[jsonDictionary[@"response"] allKeys]];

 // sort as asending order
 NSSortDescriptor* sortOrder = [NSSortDescriptor sortDescriptorWithKey: @"self" ascending: YES];
 key =  (NSMutableArray *)[key sortedArrayUsingDescriptors: [NSArray arrayWithObject: sortOrder]];

 // access inner data from dictonary
 for (NSString * obj in key) {

            NSLog(@"%@",jsonDictionary[@"response"][obj][@"name"]);

 }

Answer 1

这里的回复是字典。

如果您使用的是AFNetworking，则只需将回复作为NSDictionary进行访问即可。您可以通过访问密钥来获取值。

NSDictionary *aniDict =[ responseDict objectForKey:@"ANI"];将返回ANI键下的对象。

也可以访问嵌套词典的新词典。

NSString *name = [aniDict valueForKey:@"name"];
int age =  [[aniDict objectForKey:@"age"] integerValue];

数字和bool是字典中的NSSNumber个实例，需要解包。

Answer 2

首先解析响应数据，如下所示：

NSData *responseData;
        NSError *error;
        NSDictionary *jSONDictonary = [NSJSONSerialization dataWithJSONObject:responseData options:kNilOptions error:&error];

        NSArray *allKeys = [jSONDictonary allKeys];

然后在cellforRowAtIndexpath方法中编写以下代码：

cell.mainName.text  = [allKeys objectAtIndex:indexpath.row];
    cell.namelabel.text = [jSONDictonary valueForKeyPath:[NSString stringWithFormat:@"%@.name",[allKeys objectAtIndex:indexpath.row]]];
    cell.ageLabel.text  = [jSONDictonary valueForKeyPath:[NSString stringWithFormat:@"%@.age",[allKeys objectAtIndex:indexpath.row]]];

Answer 3

联系您的脚本制作者并致电他制作此类剧本

     response : [

                 {  
                     id=ANI;
                     name = "anisharmu";
                     age  = "10";

                  }

              {      id =ROC;  
                     name = "rockins";
                     age  = "20";
              }
                  ];
        }
    NSMutableArray *ArrData=[responseDict objecforKeys:@"response"];//all data in array now just put it in your tableview
    int i=[ArrData count];//all keys



- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView

{

    return 1;

}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section

{

    return [ArrData count];

}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath

{

    NSString *CellIdentifier = [NSString stringWithFormat:@"cell %ld",(long)indexPath.row];



    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];



    cell = nil;

    if (cell == nil)

    {

        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease];

        UILabel *lbl_id=[[UILabel alloc] initWithFrame:CGRectMake(10, 10, 100, 40)];
        lbl_id.text = [[ArrData objectAtIndex:indexPath.row] objectForKey:@"id"];
        [cell.contentView addSubview:lbl_id];
        lbl_id.layer.borderColor=[UIColor blueColor].CGColor;
        lbl_id.layer.borderWidth=4.0;
        [lbl_id release];

        UILabel *lblName=[[UILabel alloc] initWithFrame:CGRectMake(10, 40, 100, 40)];
        lblName.text = [[ArrData objectAtIndex:indexPath.row] objectForKey:@"name"];
        [cell.contentView addSubview:lblName];
        lblName.layer.borderColor=[UIColor blueColor].CGColor;
        lblName.layer.borderWidth=4.0;

        [lblName release];

        UILabel *lblage=[[UILabel alloc] initWithFrame:CGRectMake(10, 70, 100, 40)];
        lblage.text=[[ArrData objectAtIndex:indexPath.row] objectForKey:@"age"];
        [cell.contentView addSubview:lblage];
        lblage.layer.borderColor=[UIColor blueColor].CGColor;
        [lblage release];



    }



    return cell;

}

如何获取嵌套的JSON值并将其加载到Tableview Objective c中？

3 个答案: