Question

我有2个具有一对多关系项目和原型的实体我一直在寻找一种方法来列出属于show动作中项目的原型。这是我的项目实体：

<?php

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Projet
 *
 * @ORM\Table()
 * @ORM\Entity(repositoryClass="AppBundle\Entity\ProjetRepository")
 */

class Projet
{
/**
 * @var integer
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $id;

/**
 * @var string
 *
 * @ORM\Column(name="nom", type="string", length=255)
 */
private $nom;

/**
 * @var string
 *
 * @ORM\Column(name="description", type="string", length=255)
 */
private $description;

/**
 * @var \DateTime
 *
 * @ORM\Column(name="dateCreation", type="date")
 */
private $dateCreation;

/**
 * @ORM\OneToMany(targetEntity="AppBundle\Entity\Prototype", mappedBy="projet",cascade={"persist"} , orphanRemoval=true)
 * @ORM\OrderBy({"id"="ASC"})
 */
protected $prototypes;


public function __construct()
{   
    $this->prototypes = new \Doctrine\Common\Collections\ArrayCollection();
    $this->dateCreation =  new \DateTime("now");
}

/**
 * Get id
 *
 * @return integer 
 */
public function getId()
{
    return $this->id;
}

/**
 * Set nom
 *
 * @param string $nom
 * @return Projet
 */
public function setNom($nom)
{
    $this->nom = $nom;

    return $this;
}

/**
 * Get nom
 *
 * @return string 
 */
public function getNom()
{
    return $this->nom;
}

public function __toString()
{
return $this->getNom();
}

/**
 * Set description
 *
 * @param string $description
 * @return Projet
 */
public function setDescription($description)
{
    $this->description = $description;

    return $this;
}

/**
 * Get description
 *
 * @return string 
 */
public function getDescription()
{
    return $this->description;
}

/**
 * Set dateCreation
 *
 * @param \DateTime $dateCreation
 * @return Projet
 */
public function setDateCreation($dateCreation)
{
    $this->dateCreation = $dateCreation;

    return $this;
}

/**
 * Get dateCreation
 *
 * @return \DateTime 
 */
public function getDateCreation()
{
    return $this->dateCreation;
}


public function setPrototypes($prototypes)
{
if (count($prototypes) > 0) {
    foreach ($prototypes as $i) {
        $this->addPrototypes($i);
    }
}

return $this;
}

/**
 * Add prototypes
 *
 * @param \AppBundle\Entity\Prototype $prototypes
 * @return Projet
 */
public function addPrototypes(\AppBundle\Entity\Prototype $prototypes)
{
$this->prototypes[]= $prototypes;
return $this;
}

public function addPrototype(\AppBundle\Entity\Prototype $prototype)
{
$prototype->setProjet($this);
$this->prototypes->add($prototype);
}


/**
 * Remove prototypes
 *
 * @param \AppBunble\Entity\Prototype $prototypes
 */
public function removePrototypes(\AppBundle\Entity\Prototype $prototypes)
{
$this->prototypes->removeElement($prototypes);
}



/**
 * Get prototypes
 *
 * @return \Doctrine\Common\Collections\Collection 
 */

public function getPrototypes()
{
return $this->prototypes;
}



}

这是我的原型实体

<?php

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Prototype
 *
 * @ORM\Table()
 * @ORM\Entity(repositoryClass="AppBundle\Entity\PrototypeRepository")
 */
class Prototype
{
/**
 * @var integer
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $id;

/**
 * @var string
 *
 * @ORM\Column(name="nom", type="string", length=255)
 */
private $nom;


/**
 * @var string
 *
 * @ORM\Column(name="description", type="string", length=255)
 */
private $description;

/**
 * @var \DateTime
 *
 * @ORM\Column(name="dateCreation", type="date")
 */
private $dateCreation;


/**
 * @ORM\ManyToOne(targetEntity="AppBundle\Entity\Projet", inversedBy="prototypes")
 * @ORM\joinColumn(name="projet_id", referencedColumnName="id")
 */
private $projet;

/**
 * Get id
 *
 * @return integer 
 */
public function getId()
{
    return $this->id;
}


/**
 * Get nom
 *
 * @return string 
 */
public function getNom()
{
    return $this->nom;
}

public function __toString()
{
return $this->getNom();
}

/**
 * Set nom
 *
 * @param string $nom
 * @return Prototype
 */
public function setNom($nom)
{
    $this->nom = $nom;

    return $this;
}


/**
 * Set description
 *
 * @param string $description
 * @return Prototype
 */
public function setDescription($description)
{
    $this->description = $description;

    return $this;
}

/**
 * Get description
 *
 * @return string 
 */
public function getDescription()
{
    return $this->description;
}

/**
 * Set dateCreation
 *
 * @param \DateTime $dateCreation
 * @return Prototype
 */
public function setDateCreation($dateCreation)
{
    $this->dateCreation = $dateCreation;

    return $this;
}

/**
 * Get dateCreation
 *
 * @return \DateTime 
 */
public function getDateCreation()
{
    return $this->dateCreation;
}




/**
 * Set projet
 *
 * @param \AppBundle\Entity\Projet $projet
 * @return Prototype
 */
public function setProjet(\AppBundle\Entity\Projet $projet = null)
{
    $this->projet = $projet;

    return $this;
}

/**
 * Get projet
 *
 * @return \AppBundle\Entity\Projet 
 */
public function getProjet()
{
    return $this->projet;
}
}

在我的projetAdmin中，我可以在ShowAction中显示原型：这是projetAdmin：

<?php


namespace AppBundle\Admin;

use Sonata\AdminBundle\Admin\Admin;
use Sonata\AdminBundle\Datagrid\ListMapper;
use Sonata\AdminBundle\Datagrid\DatagridMapper;
use Sonata\AdminBundle\Form\FormMapper;
use Sonata\AdminBundle\Show\ShowMapper;
use Sonata\AdminBundle\Route\RouteCollection;


class ProjetAdmin extends Admin
{   

protected function configureFormFields(FormMapper $formMapper)
{
    $formMapper
        ->add('nom', 'text', array('label' => 'Nom'))
        ->add('description','text',array('label'=>'Description'))
        ->add('dateCreation', 'date', array('label' => 'Date de création'))


        ;
}

protected function configureDatagridFilters(DatagridMapper $datagridMapper)
{
    $datagridMapper
        ->add('nom')
        ->add('dateCreation')

    ;
}


protected function configureListFields(ListMapper $listMapper)
{
    $listMapper

        ->add('nom')
        ->add('description')
        ->add('dateCreation')
        ->add('_action', 'actions', array(
                'actions' => array(
                'show' => array(),
                'edit' => array(),
                'delete' => array(),
            )
        )
        )

    ;
}



protected function configureShowFields(ShowMapper $showMapper)
{
    $showMapper

    ->add('prototypes')


;

}



}

我得到了原型（名称）

但我想＆＃34;列出＆＃34;属于项目的原型，如列表视图（名称，原型描述......）

我该怎么做？

Answer 1

一种方法是在prototypes

中为showMapper字段定义模板

protected function configureShowFields(ShowMapper $showMapper)
{
    $showMapper ->add('prototypes',null, array('template' => 'NamespaceYourBundle::Admin/prototypes.html.twig'));

}

在您的包的资源文件夹中创建Admin文件夹并创建prototypes.html.twig文件，使用奏鸣曲的base_show_field.html.twig模板扩展您的树枝模板，并在{% block field %}中定义您自己的标记循环遍历所有相关原型

{% extends 'SonataAdminBundle:CRUD:base_show_field.html.twig' %}
{% block field %}
    {% spaceless %}
        {% if object.getPrototypes() is not empty %}
            <table class="table table-bordered table-striped">
            <thead>
            <tr class="sonata-ba-list-field-header">
            <th class="sonata-ba-list-field-header-text">Nom</th>
            <th class="sonata-ba-list-field-header-text">Description</th>
                ...
                ...
                ...
            </tr>
            </thead>
            <tbody>
            {% for prototype in object.getPrototypes() %}
            <tr>
                <td class="sonata-ba-list-field sonata-ba-list-field-text">{{ prototype.getNom() }}</td>
                <td class="sonata-ba-list-field sonata-ba-list-field-text">{{ prototype.getDescription() }}</td>
                ...
                ...
                ...
            </tr>
            {% endfor %}
            </tbody>
            </table>
        {% endif %}
    {% endspaceless %}
{% endblock %}

Answer 2

我找到了解决问题的方法，但我觉得这不是更好的方法我创建了一个控制器并覆盖了showAction

<?php


namespace AppBundle\Controller;


use Sonata\AdminBundle\Route\RouteCollection;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Sonata\AdminBundle\Controller\CRUDController as Controller;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;

class CRUDController extends Controller
{

    public function showAction($id = null)
    {
        return $this->redirect($this->generateUrl('admin_app_prototype_list', array(
        'filter[projet__id][value]'=>$id
    )));
    }
}

然后我得到一个属于项目的原型列表。

Sonata管理员捆绑，操纵对象

2 个答案: