无限的CGfloat数组

Question

我正在尝试在swift中创建一个无界数组。我找到了分配Ints和基本Floats的无界数组的例子，但是当我尝试将数组转换为CGFloats数组时，我发现了一些问题。下面的snipet有一个名为vertices的数组，我相信我已经将它定义为CGFloats的无界数组。一旦我尝试索引CGfloats，编译器就会抱怨无法下标类型＆＃39; [（GLfloat）]＆＃39;索引类型＆＃39;（（Int32））＆＃39;也许我不能真正理解错误告诉我的是什么。任何人都可以通过使用Int？

订阅CGfloat数组来解释这个问题

private func makeSomeCoords(cx: Float, cy: Float, cz: Float, r: Float, p:Int32)
{
    var theta1 = 0.0 as Float
    var theta2 = 0.0 as Float
    var theta3 = 0.0 as Float
    var ex = 0.0 as GLfloat
    var ey = 0.0 as GLfloat
    var ez = 0.0 as GLfloat
    var px = 0.0 as GLfloat
    var py = 0.0 as GLfloat
    var pz = 0.0 as GLfloat

    var vertices = [GLfloat]()  // <= My presumption is these are not declared correctly
    var normals = [GLfloat]()
    var texCoords = [GLfloat]()

    var abs_r = r as Float
    var abs_p = p as Int32

    if( abs_r < 0.0 ) {
        abs_r = -abs_r
    }

    if(abs_p < 0 ) {
        abs_p = -abs_p
    }

    for var i = 0 as Int32; i < p/2; ++i  {
        var i_fl = Float(i) as Float
        theta1 = i_fl * (Float(M_PI)*2.0) / Float(abs_p) - Float(M_PI_2)
        theta2 = (i_fl + 1.0) * (Float(M_PI)*2) / Float(abs_p) - Float(M_PI_2)

        for var j = 0 as Int32; j <= abs_p; ++j {
            theta3 = Float(j) * (Float(M_PI)*2) / Float(abs_p)

            ex = cosf(theta2) * cosf(theta3)
            ey = sinf(theta2)
            ez = cosf(theta2) * sinf(theta3)
            px = cx + abs_r * ex
            py = cy + abs_r * ey
            pz = cz + abs_r * ez

            vertices[((6*j)+(0%6))] = px  <= Complains Cannot subscript a value of type '[(GLfloat)]' with an index of type '((Int32))'
            vertices[((6*j)+(1%6))] = py
            vertices[((6*j)+(2%6))] = pz

            normals[(6*j)+(0%6)] = ex
            normals[(6*j)+(1%6)] = ey
            normals[(6*j)+(2%6)] = ez

        }

    }
}