Question

我正在尝试按照此YouTube教程使用OAuth 2.0导入Google通讯录：Tutoriel PHP - Importer des contacts Google。但是，目前没有显示按钮链接。

这是我的index.php文件的代码：

<?php session_start(); ?>
<!DOCTYPE html>
<html class="no-js" lang="en"/>
    <head>
        <meta charset="utf-8" />
        <meta name="viewport" content="width=device-width" />
        <title>Google Contacts API</title>
    </head>
    <body>
        <h2>Google Contacts API v3.0</h2>
<?php
    require 'config.php';
    require 'lib/google-api-client/Google_Client.php';

    $client_id = '<aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa.bbbbbb.cccccccccccc.com>';
    $client_secret = '<e3fsfds4gfg23ha93kmKFkfgK>';
    $redirect_uri = '<http://ccccccccccccccccccc.com/rddddddddddd/index.php>';

    $client = new Google_Client();
    $client -> setApplicationName('contact');
    $client -> setClientid($client_id);
    $client -> setClientSecret($client_secret);
    $client -> setScopes('https://www.google.com/m8/feeds');
    $client -> setRedirectUri($redirect_uri);
    $client -> setAccessType('online');

    if (isset($_GET['code'])) {
        $client->authenticate();
        $_SESSION['token'] = $client->getAccessToken();
        header('Location: ' . $google_redirect_uri);
    }

    if(!isset($_SESSION['token'])) {
        $url = $client->createAuhUrl();
?>
        <a href="<?=$url; ?>">Import Google Contacts</a>
<?php
    } else {
        $client->setAccessToken($_SESSION['token']);
        $token = json_decode($_SESSION['token']);
        $token->access_token;
        $curl = curl_init("https://www.google.com/m8/feeds/contacts/default/full?alt=json&max-results=50&access_token=" . $token->access_token);
        curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
        curl_setopt($curl, CURLOPT_TIMEOUT, 10);
        $contacts_json = curl_exec($curl);
        curl_close($curl);
        $contacts = json_decode($contacts_json, true);
        $return = array();
        foreach($contacts['feed']['entry'] as $contact) {
            $return[] = array(
            'name' => $contact['title']['$t'],
            'email' => isset($contact['gd$email'][0]['address']) ? $contact['gd$email'][0]['address'] : false,
            'phone' => isset($contact['gd$phoneNumber'][0]['$t']) ? $contact['gd$phoneNumber'][0]['$t'] :false,
            );
        }
        var_dump($return);
    }       
?>
    </body>
</html>

我如何更正此问题？

Answer 1

只有在if(!isset($_SESSION['token']))为假时才会显示。

令牌未设置？

echo $_SESSION['token'];在<h2>Google Contacts API v3.0</h2>之后确定。

这样做也是浪费：

if(!isset($_SESSION['token'])){
    $url = $client->createAuhUrl();
    ?>
        <a href="<?=$url; ?>">Import Google Contacts</a>
    <?php
} else {

请改为：

if(!isset($_SESSION['token'])){
    $url = $client->createAuhUrl();
    echo '<a href="' . $url . '">Import Google Contacts</a>';
} else {

如果HTML内容的数量很大，那么只能打败PHP。

Answer 2

我不了解PHP，

但解决方案是您必须为href添加一些链接，如

<a href="www.google.com">test</a>

或

<a href="#">test</a>

Answer 3

您可以像这样放置代码，了解问题

if(isset($_SESSION['token'])){
$url = $client->createAuhUrl();
?>
    <a href="<?=$url; ?>">Import Google Contacts</a>
<?php
} else {

无法显示<a href=""></a>按钮链接

3 个答案: